Answer: -112200J
Explanation:
The amount of heat (Q) released from an heated substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)
Thus, Q = MCΦ
Since,
Q = ?
Mass of water vapour = 30.0g
C = 187 J/ G°C
Φ = (Final temperature - Initial temperature)
= 100°C - 120°C = -20°C
Then apply the formula, Q = MCΦ
Q = 30.0g x 187 J/ G°C x -20°C
Q = -112200J (The negative sign does indicates that heat was released to the surroundings)
Thus, -112200 joules of heat is released when cooling the superheated vapour.
Answer:
It contain double Bond.
Explanation:
To determine weather the bond is double or triple simply check the electron involved in mutual sharing of an electron if 2 electron takes parts it said to be double or if 3 it said to be triple.
Mass of C = 12g
mass of H = 1g
mass of O = 16g
mass of C2H5OH = 46g = 1 mole
1 mole of C2H5OH ------------ 46g
x moles of C2H5OH ----------- 230g
x = 5 moles of C2H5OH
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
mass of C = 12g
mass of H = 1g
mass of C2H4 = 28g = 1 mole
1 mole of C2H4 -------------- 28g
x moles of C2H4 ------------- 560g
x = 20 moles of C2H4
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
mass of S = 32g
mass of O = 16g
mass of SO2 = 64g = 1 mole
1 mole of SO2--------------------- 64g
x mole of SO2 -------------------- 0,64g
x = 0,01 moles of SO2
That’s looks weird to be honest i have no ideas
