PLEASE ANSWER ASAP

In the aerials competition in skiing, the competitors speed down a ramp that slopes sharply upward at the end. the sharp upward

ladessa [460]

<u>Answer:</u>

The skier’s launch speed = 17.08 m/s

<u>Explanation:</u>

The motion of skiing is projectile motion.

Projectile motion has two types of motion Horizontal and Vertical motion.

Vertical motion:

We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

Considering upward vertical motion of projectile.

In this case, Initial velocity = vertical component of velocity = u sin θ, acceleration = acceleration due to gravity = -g $m/s^2$ and final velocity = 0 m/s.

0 = u sin θ - gt

t = u sin θ/g

Total time for vertical motion is two times time taken for upward vertical motion of projectile.

So total travel time of projectile = 2u sin θ/g

Horizontal motion:

We have equation of motion , $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In this case Initial velocity = horizontal component of velocity = u cos θ, acceleration = 0 $m/s^2$ and time taken = 2u sin θ /g

So range of projectile, $R=ucos\theta*\frac{2u sin\theta}{g} = \frac{u^2sin2\theta}{g}$

Vertical motion (Maximum height reached, H) :

We have equation of motion, $v^2=u^2+2as$ , where u is the initial velocity, v is the final velocity, s is the displacement and a is the acceleration.

Initial velocity = vertical component of velocity = u sin θ, acceleration = -g, final velocity = 0 m/s at maximum height H

$0^2=(usin\theta) ^2-2gH\\ \\ H=\frac{u^2sin^2\theta}{2g}$

We have θ = 63° and H = 11.8 meter.

Substituting

$11.8=\frac{u^2sin^263}{2*9.81}\\ \\ u^2=\frac{11.8*2*9.81}{sin^263}=\frac{231.516}{0.794} =291.58\\ \\ u=17.08m/s$

The skier’s launch speed = 17.08 m/s

3 0

4 years ago

Read 2 more answers

DO NOT ANSWER IF YOU DONT KNOW What is the medium for a wave:

Thepotemich [5.8K]

Water fans/people air

5 0

3 years ago

An astronaut in her space suit has a total mass of 87.0kg including suit and oxygen tank. Her tether line loses its attachment t

Shtirlitz [24]

Answer:

Explanation:

a )

In space due to weightlessness both astronaut and her oxygen tank will float .

when she throws the tank away from spacecraft , she will have a velocity in opposite direction ie towards the spacecraft . This happens due to conservation of momentum . She creates a momentum away so that she can get a momentum towards the spaceship.

So

m₁ v₁ = m₂v₂

12 x 8 = ( 87 - 12 ) x v₂

v₂ = 1.28 m /s

Time allowed = 2 x 60

= 120 s

So maximum distance upto which she can remain away from spacecraft

= 120 x 1.28

= 153 m .

b )

The Newton's law which explains the theory behind it is "third law of motion" . This law gives law of conservation of momentum .

6 0

4 years ago

A 5 kg pineapple is hanging completely still in mid air on a string and suddenly explodes

11111nata11111 [884]

Answer:

Explanation:

Conservation of momentum

Initial momentum is zero

3(15) + 2(v) = 0

v = - 22.5 m/s

v = 22.5 m/s downward

3 0

3 years ago

Place the single weight with a known mass on the spring and release it. Eventually, the weight will come to rest at an equilibri

aliya0001 [1]

Answer:

X=m*g/K

Explanation:

Since the elastic force of the spring is balancing the force of gravity:

Fe = m*g

Now, on the spring by Hook's law, the magnitude of the elastic force will be:

Fe = K*X where K is the elastic constant of the spring and X is the distance the spring is strectches measured from its original lenght to its current length.

Replacing this value:

K*X = m*g Solving for X:

X = m*g/K This value is directly proportional to the object's weight and inversely proportional to the spring's constant.

3 0

4 years ago