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BlackZzzverrR [31]
3 years ago
7

There are billions of galaxies in the Universe. How are they classified?

Physics
1 answer:
denis23 [38]3 years ago
6 0
By their size and color
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Distinguish between endangered and extinct species.
Julli [10]

Answer and Explanation:

The distinction between Endangered species and Extict species is Given as under:

Endangered Species:

Endangered species are categorized as those species of flora and fauna which are on the verge of extinction if not provided timely protection in order to save them from getting extinct.

Some of the endangered species are African Penguin, Bengal Tiger, Blue Whale, etc

Extinct Species:

Those species of Flora and Fauna which have vanished completely or either from the wild i.e., that individuals of that species are not alive any more and have completely disappear from the earth.

In practice, if a species is not seen for over a period of 50 years it is considered to be extinct.

Some of the extinct species are Dodo, Passenger Pigeon, Great Aulk, etc.  

7 0
3 years ago
What is Newtens first law of motion​
OlgaM077 [116]

Newtons first law states that an object will remain still or in straight line. Until acted upon some force!

4 0
3 years ago
Read 2 more answers
When a negatively charged object moves in the opposite direction of an electric force field, the potential energy of the object
Simora [160]
The best and most correct answer among the choices provided by the question is decreases <span>.


</span>The potential energy of the object <span>decreases.</span>

Hope my answer would be a great help for you.    
If you have more questions feel free to ask here at Brainly.
3 0
3 years ago
Read 2 more answers
How long is a string under 240 N of tension whose mass is 0.086 kg if a wave travels through it at a speed of 12 m/s?
Darina [25.2K]

Answer:

The length of the string is 0.051 meters

Explanation:

It is given that,

Tension in the string, T = 240 N

Mass of the string, m = 0.086 kg

Speed of the wave, v = 12 m/s

The speed of the wave on the string is given by :

v=\sqrt{\dfrac{T}{M}}

M is the mass per unit length of the string i.e. M = m/l.......(1)

So, M=\dfrac{T}{v^2}

M=\dfrac{240\ N}{(12\ m/s)^2}

M = 1.67 kg/m

The length of the string can be calculated using equation (1) :

l=\dfrac{m}{M}

l=\dfrac{0.086\ kg}{1.67\ kg/m}

l = 0.051 m

So, the length of the string is 0.051 meters. Hence, this is the required solution.

6 0
3 years ago
A charged box (m=445 g, ????=+2.50 μC) is placed on a frictionless incline plane. Another charged box (????=+75.0 μC) is fixed i
victus00 [196]

The concept required to perform this exercise is given by the coulomb law.

The force expressed according to this law is given by

F= \frac{kqQ}{r^2}

Where,

k = 8.99 * 10^9 N m^2 / C^2.

q = charges of the objects

r= distance/radius

Our values are previously given, so

q= 2.5*10^{-6}C\\Q= 75*10^{-6}C\\r=0.59

Replacing,

F=\frac{kqQ}{r^2}

F= \frac{(8.99 x 10^9)(2.5*10^{-6})(75*10^{-6})}{0.59^2}

F= 4.8423N

The force acting on the block are given by,

F-mgsin\theta = ma

a = \frac{F-mgsin\theta}{m}

a = \frac{4.8423-(0.445)(9.8)sin(35)}{0.445}a = 10.31m/s^2

Therefore the box is accelerated upward.

3 0
3 years ago
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