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scoray [572]
3 years ago
5

Which values of k would cause this system of equations to have no solution? Check all that apply.

Mathematics
2 answers:
xeze [42]3 years ago
5 0

Answer:

x= -2y/3

-4y+4y=14

0y= 14

This has no solution.

Step-by-step explanation:

Answer In cases of two equations having two unknown variables the simultaneous method of solving the equations is adopted.

Supposing “0” as the value of “k” we will have the equation as 3x+2y=0

Then separating variable x will give, x= -2y/3

Substituting the value of x into the first equation that is: 6x + 4y = 14

6(-2y/3)+4y=14

Expanding this we get: 6(-2y/3)+4y=14

-4y+4y=14

0y= 14

Thus, no solution.

8_murik_8 [283]3 years ago
3 0

Answer:

I know im late but the correct answers are

–2

5

10

21

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