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Dima020 [189]
3 years ago
14

Pre-Cal Help?!?! Solve e^x^2-9=1

Mathematics
1 answer:
andrey2020 [161]3 years ago
5 0
E^x^2 - 9 = 1
e^x^2 = 1 + 9 = 10
Ln e^x^2 = Ln 10
x^2 = Ln 10
x = sqrt (Ln 10) = 1.517
x = 1.517
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Find the larger of the two roots of the equation y = -2.2x2 + 63.5x - 17
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The larger of the two roots of the equation y = -2.2x^2 + 63.5x - 17would be 28.59.

<h3>How to find the roots of a quadratic equation?</h3>

Suppose that the given quadratic equation is

ax^2 + bx + c = 0

Then its roots are given as:

x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

The given quadratic equation is

y = -2.2x^2 + 63.5x - 17

now, the roots of the equation are

x = \dfrac{-63.5 \pm \sqrt{63.5^2 - 4(-2.2)(-17)}}{2(-2.2)}\\\\\\x = \dfrac{-63.5 \pm \sqrt{4032.25 - 149.6}}{(-4.4)}\\\\\\x = \dfrac{-63.5 \pm \sqrt{3882.65}}{(-4.4)}\\\\\\x = \dfrac{-63.5 \pm 62.31}{(-4.4)}

The two roots are 0.27 and 28.59.

Thus, the larger of the two roots of the equation y = -2.2x^2 + 63.5x - 17would be 28.59.

Learn more about finding the solutions of a quadratic equation here:

brainly.com/question/3358603

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