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3 years ago

Pre-Cal Help?!?! Solve e^x^2-9=1

Mathematics

1 answer:

andrey2020 [161]3 years ago

5 0

E^x^2 - 9 = 1
e^x^2 = 1 + 9 = 10
Ln e^x^2 = Ln 10
x^2 = Ln 10
x = sqrt (Ln 10) = 1.517
x = 1.517

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Find the larger of the two roots of the equation y = -2.2x2 + 63.5x - 17

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The larger of the two roots of the equation $y = -2.2x^2 + 63.5x - 17$ would be 28.59.

<h3>How to find the roots of a quadratic equation?</h3>

Suppose that the given quadratic equation is

$ax^2 + bx + c = 0$

Then its roots are given as:

$x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

The given quadratic equation is

$y = -2.2x^2 + 63.5x - 17$

now, the roots of the equation are

$x = \dfrac{-63.5 \pm \sqrt{63.5^2 - 4(-2.2)(-17)}}{2(-2.2)}\\\\\\x = \dfrac{-63.5 \pm \sqrt{4032.25 - 149.6}}{(-4.4)}\\\\\\x = \dfrac{-63.5 \pm \sqrt{3882.65}}{(-4.4)}\\\\\\x = \dfrac{-63.5 \pm 62.31}{(-4.4)}$

The two roots are 0.27 and 28.59.

Thus, the larger of the two roots of the equation $y = -2.2x^2 + 63.5x - 17$ would be 28.59.

Learn more about finding the solutions of a quadratic equation here:

brainly.com/question/3358603

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