Answer:
Explanation:
Hello,
In this case, the unit of concentration is molality which is defined by:
Whereas the mass of the solvent is measured in kilograms. In such a way, with the given data, we first compute the kilograms of water:
Then, we solve for the moles of the solute:
Finally since the molar mass of ethanol is 46 g/mol, we compute the grams for the given solution:
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Answer:
D.
Explanation:
CH₃C≡ CCH₂CH₂Cl
Since there are 5 carbons so the suffix used is "pent"
There is a triple bond so its alkyne
So the compound becomes 2-pentyne (2 because the triple bond is with the 2nd carbon)
Then,
The functional group of chlorine is attached with 5th carbon So the compound becomes
5-chloro,2-pentyne
Lowery-Bronsted theory is applied here. Acc. to this theory Base accepts protons and Acids donate proton.
Part 1:
Aniline is less basic than ethylamine because the lone pair on nitrogen (which accepts proton) is not localized. It resonates throughout the conjugated system of phenyl ring. Hence due to unavailability of electrons for accepting proton it is less basic compare to ethylamine. In ethyl amine the lone pair of electron is localized and available to abstract proton.
Part 2:
In this case the alkyl groups attached to -NH₂ (in ethylamine) and -O⁻ (in ethoxide are same (i.e. CH₃-CH₂-). Ethoxide is more basic than ethylamine because ethoxide is a conjugate base of ethanol (pKa value of ethanol = 15.9 very weak acid) and the conjugate base of weak acid is always a strong base. Secondly, the oxygen atom more Electronegative than Nitrogen atom can attract more electron cloud from alkyl group as compared to Nitrogen in ethylamine. Hence, oxygen in ethoxide attains greater electron cloud than the nitrogen in ethylamine. Therefore, it is more basic than ethylamine.
M = mols of solute / L of solution
Convert .50 g Na to mols Na by dividing by 22.99 and then dividing that by 1.5, which gives you a 0.014 M solution.
