Question

A 10.0 L balloon is taken from a warm room that is 24 °C to outside in the winter weather where it is 3.8 °C. What is its new volume?

Answer 1

9.32 is the new volume of the balloon.

Explanation:

Data given:

Initial volume of the balloon V1 = 10 litres

initial temperature in the room T1 = 24 degrees 0r 297.15 K

final volume V2=?

final temperature T2 = 3.8 degrees OR 276.95

from the values given it is deduced that we have to apply Charles Law

$\frac{V1}{T1}$ = $\frac{V2}{T2}$

V2 = $\frac{V1T2}{T1}$

putting the values in the equation:

V2 - $\frac{10 x 276.95}{297.15}$

V2 = 9.32 liter

When baloon is taken from a warm room to outside where it is cold the volume of the gas becomes 9.32 litre in the balloon