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Nastasia [14]
3 years ago
7

Ray puts a glass of ice water on the table. One hour later he observes that only water is left in the glass. What happened?

Chemistry
2 answers:
tankabanditka [31]3 years ago
6 0

Answer:

  • The ice in the glass melted into liquid water (a physical change, known and change of phase)

Explanation:

Heat flows from warmer substances to cooler substances.

Ice water contents ice (solid water) and liquid water.

Ice freezes at 0°C and below.

Ice is the solid state of water; at this stage, the water molecules have low kinetic energy and the remain vibrating around a relatively fixed position in a crystal structure.

The liquid water around the solid ice cubes has a larger kinetic energy than the cubes. Also, the environment is at a higher temperature than the content of the glass.

Hence, both heat from the room and heat from the liquid water will flow toward the cooler ice cubes. The molecules that form the ice cubes will gain kinetic energy, causing the temperature of the ice cubes increase; the molecules will vibrate faster until they can move and slide past each other, which means that they have become liquid (melted).

This is a physical change known as change of phase, specifically melting.

vekshin13 years ago
4 0

Answer:

Ice Water

Explanation:

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If the solution feel slippery and has a pH of 12, what is the solution
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4 years ago
determine the freezing point depression of a solution that contains 30.7 g glycerin (c3h8o3, molar mass
Blababa [14]

The freezing point depression of a solution containing 30.7 g of glycerin  is  calculated as -1.65°C

Equating :

It is given that,

Given mass of glycerin is = 30.7 grams (Solute)

Volume of water = 376 mL

K_{f}or molar -freezing-depression point is = 1.86°C/m

Molar mass of glycerin = 92.09 g/mole

Now, to work out the value, the mass of water should be known. Thus, to calculate, the formula used will be:

Mass = Density X Volume

Mass = 1.0 g/mL X 376 mL

Mass = 376 g or 0.376 Kg

Using the formula of melting point depression, the equation becomes:

             ΔT_{f} = i ×K_{f} ×m

T⁰-T_{s}  = i *K_{f} *\frac{mass of glycerin}{molar mass of glycerin * mass of water     in     kg}

in which,

ΔT_{f} = change in freezing point

ΔT_{s} = freezing point of solution that has to be find

ΔT° = freezing point of water ()

Since, glycerin is a non-electrolyte, the Van't Hoff factor will be 1.

Substituting the values in the above equation:

0⁰C₋T_{s} = 1 ×1.86°C/m ×\frac{30.7}{92.09g/mol * 0.376kg}

T_{s} = -1.65°C

Thus, the freezing point depression of a solution is  -1.65°C

<h2 />

Freezing point depression

Freezing point depression is a colligative property observed in solutions that results from the introduction of solute molecules to a solvent. The freezing points of solutions are all less than that of the pure solvent and is directly proportional to the molality of the solute

Is melting point elevation or depression?

Boiling point elevation is that the raising of a solvent's boiling point due to the addition of a solute. Similarly, melting point depression is the lowering of a solvent's freezing point due to the addition of a solute. In fact, because the boiling point of a solvent increases, its melting point decreases

Learn more about freezing point depression :

brainly.com/question/26525184

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