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Nastasia [14]
3 years ago
7

Ray puts a glass of ice water on the table. One hour later he observes that only water is left in the glass. What happened?

Chemistry
2 answers:
tankabanditka [31]3 years ago
6 0

Answer:

  • The ice in the glass melted into liquid water (a physical change, known and change of phase)

Explanation:

Heat flows from warmer substances to cooler substances.

Ice water contents ice (solid water) and liquid water.

Ice freezes at 0°C and below.

Ice is the solid state of water; at this stage, the water molecules have low kinetic energy and the remain vibrating around a relatively fixed position in a crystal structure.

The liquid water around the solid ice cubes has a larger kinetic energy than the cubes. Also, the environment is at a higher temperature than the content of the glass.

Hence, both heat from the room and heat from the liquid water will flow toward the cooler ice cubes. The molecules that form the ice cubes will gain kinetic energy, causing the temperature of the ice cubes increase; the molecules will vibrate faster until they can move and slide past each other, which means that they have become liquid (melted).

This is a physical change known as change of phase, specifically melting.

vekshin13 years ago
4 0

Answer:

Ice Water

Explanation:

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It is difficult to extinguish a fire on a crude oil tanker, because each liter of crude oil releases 2.80 × 10 7 J 2.80×107 J of
Alborosie

Answer:

The question is incorrect and incomplete. Here's the correct question:

It is difficult to extinguish a fire on a crude oil tanker, because each liter of crude oil releases 2.80 × 10 7 J  of energy when burned. To illustrate this difficulty,a) calculate the number of liters of water that must be expended to absorb the energy released by burning 1.00 L  of crude oil, if the water has its temperature raised from 23.5 °C to 100 °C , it boils, and the resulting steam is raised to 315 °C. b)Discuss additional complications caused by the fact that crude oil has less density than water.

Explanation:

Q= mc ΔT

Q= heat energy

m is mass

ΔT is change in temperature and c is specific heat capacity

calculating heat for latent heat of vaporisation

Q= ml where l is latent heat of vaporisation

a) Total heat energy used= heat required to raise temperature from 23.5 °C to 100 °C, heat required to boil water and heat required to further raise temperature from 100 °C to 315°C

Q = mc ΔT₁ + mL + mc ΔT₂

Q = m(c ΔT₁ + L + c ΔT₂)

m= Q÷(c ΔT₁ + L + c ΔT₂)

Q= 2.8 X 10⁷ J

c=4186J/kg°C

L=2256 x 10³J/kg

ΔT₁=76.5°C(100°C-23.5°C)

ΔT₂= 215°C(315°C-100°C)

(c ΔT₁ + L + c ΔT₂)= 4186J/kg°C *76.5°C + 2256 x 10³J/kg + 4186J/kg°C*215°C =3476219J/Kg

m= 2.8 x 10⁷J ÷3476219J/Kg

m =80.54 Kg

volume = mass÷ density

=80.54kg ÷ 10³kg/m³( density of water)

=0.0854m³

0.001m³ = 1 lL0.08054m³= 0.08054m³ /0.001m³= 80.54L

VOLUME is 80.54litres

b) since the density of crude is less than the density of water,and 80L of additional water is added, it'll make the crude to float on water thus inhibiting the extinguishing process

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brilliants [131]

Answer:

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Explanation:

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