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inessss [21]
3 years ago
12

How many grams of CO2 are in 11 mol of the compound?

Chemistry
1 answer:
GrogVix [38]3 years ago
8 0
Well the molar mass of CO2 would be that 1 mol of CO2 would have the mass of 44.0 grams. So 11 mol of CO2 would have 11 • 44 or 484 grams.
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What is the boiling point of an aqueous solution that has a vapor pressure of 23.0 torr at 25 ∘C? (P∘H2O=23.78 torr; Kb= 0.512 ∘
UNO [17]

Answer:

Boiling point of the solution is 100.964°C

Explanation:

In this problem, first, you must use Raoult's law to calculate molality of the solution. When you find the molality you can obtain the boiling point elevation because of the effect of the solute in the solution (Colligative properties).

Using Raoult's law:

Psol = Xwater × P°water.

As vapour pressure of the solution is 23.0torr and for the pure water is 23.78torr:

23.0torr= Xwater × 23.78torr.

0.9672 = Xwater.

The mole fraction of water is:

0.9672 = \frac{X_{H_2O}}{X_{H_2O}+X_{solute}}

Also,

1 = X_{H_2O}+X_{solute}

You can assume moles of water are 0.9672 and moles of solute are 1- 0.9672 = 0.0328 moles

Molality is defined as the ratio between moles of solute (0.0328moles) and kg of solvent. kg of solvent are:

09672mol *\frac{18.01g}{1mol}* \frac{1kg}{1000g} = 0.01742kg

Molality of the solution is:

0.0328mol Solute / 0.01742kg = 1.883m

Boiling point elevation formula is:

ΔT = Kb×m×i

<em>Where ΔT is how many °C increase the boiling point regard to pure solvent, Kb is a constant (0.512°C/m for water), m molality (1.883m) and i is Van't Hoff factor (Assuming a i=1).</em>

Replacing:

ΔT = 0.512°C/m×1.882m×1

ΔT = 0.964°C

As the boiling point of water is 100°C,

<h3>Boiling point of the solution is 100.964°C</h3>

<em />

5 0
3 years ago
How do plants release energy
ololo11 [35]

Answer:

no but oxygen

Explanation:

no but oxygen

7 0
3 years ago
Read 2 more answers
How many moles of KCL is in a 3M solution of KCL
netineya [11]

Answer:

223.6539

Explanation:

1 mole is equal to 1 moles KCl, or 74.5513 grams

4 0
3 years ago
Marcus measured the masses and volumes of samples of four different substances, and he calculated their densities. The table sho
Zina [86]

<u>Given:</u>

Calculated density values-

Aluminum = 2.7 g/cm3

Copper = 9.0 g/cm3

Iron = 7.9 g/cm3

Titanium = 4.8 g/cm3

Unknown sample mass = 9.5 g

Sample volume = 2.1 cm3

<u>To determine:</u>

The identity of the unknown sample

<u>Explanation:</u>

'Density' is a physical parameter which can be used to identify the nature of the unknown substance.

Density = Mass/Volume

For the unknown sample

Density = 9.5 g/2.1 cm3 = 4.52 g/cm3

This matches closely with the calculated density of titanium

Ans: The unknown substance is made of titanium

4 0
3 years ago
Which is transferred due to a temperature difference?
Sliva [168]

Answer:

A

Explanation:

heat energy is transfered through a hot object touching a cold object

5 0
3 years ago
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