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OverLord2011 [107]
3 years ago
14

What are the [H+] and [OH-] for a substance with a pH of 9.2? Show work please

Chemistry
1 answer:
Dafna1 [17]3 years ago
5 0

Explanation:

[H+]=10^-pH

[H+]=10^-9.2

[H+]=6.031x10^-10

[OH-]=1x10^-14÷[H+]

[OH-]=1x10^-14÷[6.031x10^-10]

[OH-]= 1.66x10^-5

im pretty sure this is right

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Keq for the reaction below is 2400. If the initial conditions of the reaction are a 1.0 L flask that contains 0.024 mol NO (g),
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Answer:

The answer to your question is it is not at equilibrium, it will move to the products.

Explanation:

Data

Keq = 2400

Volume = 1 L

moles of NO = 0.024

moles of N₂ = 2

moles of O₂ = 2.6

Process

1.- Determine the concentration of reactants and products

[NO] = 0.024 / 1 = 0.024

[N₂] = 2/1 = 2

[O₂] = 2.6/ 1= 2.6

2.- Balanced chemical reaction

                     N₂ + O₂    ⇒   2NO

3.- Write the equation for the equilibrium of this reaction

                     Keq = [NO]²/[N₂][O₂]

- Substitution

                    Keq = [0.024]² / [2][2.6]

-Simplification

                    Keq = 0.000576 / 5.2

-Result

                    Keq = 1.11 x 10⁻⁴

Conclusion

It is not at equilibrium, it will move to the products because the experimental Keq was lower than the Keq theoretical-

                         1.11 x 10⁻⁴ < 2400

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