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Olegator [25]
4 years ago
14

What is the [h+] concentration in a urine sample that has a ph of 6?

Chemistry
2 answers:
NISA [10]4 years ago
7 0
<h3>Answer:</h3>

           1.0 × 10⁻⁶ M       (Option-A)

<h3>Solution:</h3>

Data Given:

                  pH  =  6

                  [H⁺]  =  ?

Formula Used:

As we know pH is given as,

                                  pH  = -log [H⁺]

and,

                                  [H⁺]  =  10^-pH    ----- (1)

Putting value of pH in eq. 1,

                                  [H⁺]  =  10⁻⁶                                       ∴ 10  =  Antilog

                                  [H⁺]  =  1.0 × 10⁻⁶ M

slavikrds [6]4 years ago
7 0

Answer:

The correct answer is option a.

Explanation:

The pH of the solution is defined as negative logarithm of hydrogen ions concentration in its aqueous solution.

pH=-\log [H^+]

The pH of the urine sample = pH = 6

Concentration of hydrogen ion in the urine sample = [H^+]

6=-\log[H^+]

[H^+]=10^{-6} M

Hence, the correct answer is option a.

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marissa [1.9K]

Based on periodic trends, the most probable value for the ionic radius of K⁺ is 133 pm.

<h3>What are periodic trends?</h3>

Periodic trends are the observation which are seen in the chemical and physical elements found in the periodic table.

Periodic trends is based on the periodicity of elements.

Periodicity is the variation seen in the chemical and physical properties of the elements in the period table in a regular pattern, both down the groups and across the periods.

The periodic trends observed in metallic ions is that ionic radius of metallic ions increase down a group but decreases across a period.

Based on this periodic trend, the most likely size of the potassium ion, K⁺ is 133 pm.

In conclusion, the ionic radius of metallic ions increase down a group and decrease across a period.

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1 year ago
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A gas that occupies 4.31 litres at a pressure of 0.755 atm will have a temperature of 39.58°C. Details about temperature can be found below.

<h3>How to calculate temperature?</h3>

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