Answer:
Approximately 3.5 feet - Option B
Step-by-step explanation:
Imagine that you have this walkway around the garden, with dimensions 30 by 20 feet. This walkway has a difference of x feet between it's length, and say the dimension 30 feet. In fact it has a difference of x along both dimensions - on either ends. Therefore, the increases length and width should be 30 + 2x, and 20 + 2x, which is with respect to an increases area of 1,000 square feet.
( 30 + 2x ) 
( 20 + 2x ) = 1000 - Expand "( 30 + 2x ) ( 20 + 2x )"
600 + 100x + 4
= 1000 - Subtract 1000 on either side, making on side = 0
4 + 100x - 400 = 0 - Take the "quadratic equation formula"
( Quadratic Equation is as follows ) - 
,
,
There can't be a negative width of the walkway, hence our solution should be ( in exact terms ) 
. The approximated value however is 3.5081...or approximately 3.5 feet.
Volume of the cone = 1/3π r^2 h
So, we are given that r = 9 and h = 12
plugging in all the known values
1/3 * (3.14) * 9 * 9 * 12
= 1017.36 cm³
or
≈1017.4 cm³
Answer:
a = 55/6
Step-by-step explanation:
<u>Solving in steps:</u>
- 3/5a = 5 1/2
- 3/5a = 11/2
- a = 11/2 : 3/5
- a = 11/2*5/3
- a = 55/6 or 9 1/6
Answer;
p= (1 + sqrt. 181) / 6, (1- sqrt. 181) / 6
Hope this helps!
Answer:
I can help as welllll
Step-by-step explanation:
