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Arisa [49]
3 years ago
5

Solve for w pls help thank u

Mathematics
2 answers:
Umnica [9.8K]3 years ago
7 0

Answer:w=-7

Step-by-step explanation:

Distribute the 4 to the W and 3

masya89 [10]3 years ago
3 0

Answer:

w = -19

Step-by-step explanation:

-6w + 4(w +3) = 26

-6w + 4w + 12 = 26

simplify

-2w + 12 = 26

now get the variable and the numbers on different sides

-2w + 12 - 12 = -2w

26 + 12 = 38

-2w = 38

now divide each side by -2

-2w / -2 = w

38 / -2 = -19

w = -19

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Tina wants to build a garden in her backyard. She knows that the area of the section of the backyard she will be using is x^2-4x
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The area (A) of a rectangle is calculated by multiplying the length (L) and the width (W). In order for us to determine the possible dimensions of the section (or sides) of the rectangle, we have to factor the given area.
                                          x² - 4x - 45
                                       (x - 9)(x + 5)

<em>Thus, the possible dimensions of the rectangle are x-9 and x+5</em>. 
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3 years ago
Simplify. 4^3 x 4^4/ 4^9<br><br> A. 4^16<br><br> B. 4^2<br><br> C. 1/4^2<br><br> D 1/4
forsale [732]
The answer is A. 4^16
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3 years ago
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aleksandr82 [10.1K]

Answer:A

Step-by-step explanation:

5 0
2 years ago
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What is the value of y?
mrs_skeptik [129]
Ok so you would start by getting rid of the fraction. You should know the steps for that by now but here this is what it would look like
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3 years ago
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The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.​
Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is \dfrac{15}{2}.

To find:

The sum of first six terms.​

Solution:

We have,

S_2=6

S_4=\dfrac{15}{2}

Sum of first n terms of a GP is

S_n=\dfrac{a(1-r^n)}{1-r}              ...(i)

Putting n=2, we get

S_2=\dfrac{a(1-r^2)}{1-r}

6=\dfrac{a(1-r)(1+r)}{1-r}

6=a(1+r)                    ...(ii)

Putting n=4, we get

S_4=\dfrac{a(1-r^4)}{1-r}

\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}

\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}

\dfrac{15}{2}=6(1+r^2)            (Using (ii))

Divide both sides by 6.

\dfrac{15}{12}=(1+r^2)

\dfrac{5}{4}-1=r^2

\dfrac{5-4}{4}=r^2

\dfrac{1}{4}=r^2

Taking square root on both sides, we get

\pm \sqrt{\dfrac{1}{4}}=r

\pm \dfrac{1}{2}=r

\pm 0.5=r

Case 1: If r is positive, then using (ii) we get

6=a(1+0.5)  

6=a(1.5)  

\dfrac{6}{1.5}=a  

4=a

The sum of first 6 terms is

S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}

S_6=\dfrac{4(1-0.015625)}{0.5}

S_6=8(0.984375)

S_6=7.875

Case 2: If r is negative, then using (ii) we get

6=a(1-0.5)  

6=a(0.5)  

\dfrac{6}{0.5}=a  

12=a  

The sum of first 6 terms is

S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}

S_6=\dfrac{12(1-0.015625)}{1.5}

S_6=8(0.984375)

S_6=7.875

Therefore, the sum of the first six terms is 7.875.

5 0
2 years ago
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