Answer:
mass = 100kg
Explanation:
Hello! In order to calculate the mass, we first have to calculate the volume of the tube.
For this, we have the area (A) and the length (L) of the tube.
V = A * L
A = 100cm2 * (1m2 / 10000cm2) = 0.02m2
L = 5m
V = 0.02m2 * 5m = 0.1m2
Then we can calculate the area from the density.
Density = mass / volume
mass = density * volume = 1000 (kg / m3) * 0.1m3
mass = 100kg
Answer:
C
Explanation:
The atom has an electron configuration of 1s²2s²2p⁶3s²3p⁵.
The total numbe of electrons present in the shell is 17 electrons. To determine the group of the atom, we have to check what orbital did the last electron stop.
If it's in S-orbital, then we automatically knows it's an s-block element which could either be group 1 or 2 and can still be furthered down to know which group it's in.
But in this case, the last electron is in s-orbital. To determine the group number of p-orbitals, we'll have to consider the preceding s-orbital and add it to it, then count it in 10s.
For example, if the last two orbital is 3s² 3p¹, 2 + 1 = 3, add ten (10) to it = 13. Hence the element is in group 13.
In this case, we have 3s² 3p⁵ = 2 + 5 = 7 + 10 = 17.
Answer:
Explanation:
From the question we are told that:
Mass
Charge
Generally the equation for Total number of Atoms in Penny is mathematically given by
Since Number of electrons in a penny is
Therefore
The percentage of the atoms are ionized by this charging process is given as
<h2>
Answer:</h2>
As the name implies, a secondary standard is used by standard laboratories, which include companies involved in the preparation of reagents and kits, as well as laboratories responsible to produce quality control material for use by other laboratories. They use the primary standard as the primary calibrator or primary reference material, and they calibrate their instruments against it. Smaller labs use secondary standards to calibrate control material for analysis of unknown concentrations. For smaller labs, secondary standard serves as an external quality control. As a result, it is essential that the secondary standard be standardized against the primary standard before it can be applied.
<em>I hope this helps you</em>
<em>:)</em>
Answer: Option (A) is the correct answer.
Explanation:
It is known that in real gases, at low temperature there is existence of force of attraction between molecules of the gas.
This force of attraction occurs because at low temperature there will be a decrease in kinetic energy of gas molecules. Therefore, the molecules tend to move slowly.
Hence, when molecules come closer to each other then forces of attraction increases leading to a decrease in pressure and therefore, gases deviate from an ideal gas behavior.
Thus, we can conclude that the statement as attractive forces between molecules increase, deviations from ideal behavior become more apparent at relatively low temperatures, is true for real gases.