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Gnesinka [82]
3 years ago
10

Which of these expressions correctly expresses the solubility-product constant for ag3po4 in water?

Chemistry
1 answer:
miss Akunina [59]3 years ago
7 0
<span>[Ag+]3[PO4]3- Ag3PO4(aq) ----> 3Ag^+(aq) + PO4^3-(aq) In pure water, the molarity of PO4^3-, which is 1.76x10^-5 M, also represents the molar solubility of Ag3PO4, that means that max 1.76x10^-5 mol Ag3PO4 dissolves in 1L (1000 mL) of water. When the amount of water is halved to 500 mL, the solubility of Ag3PO4 is also halved. (8.8x10^-5 mol). Ag3PO4(aq) ----> 3Ag^+(aq) + PO4^3-(aq) 8.8x10^-5 mol ..... 3x8.8x10^-5 mol = 2.64x10^-4 mol [Ag^+] = n / V = 2.64x10^-4 mol / 0.500 L = 5.28x10^-4 M</span>
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If you'd like the full working, here it is:

I calculated this by using the formula triangle.

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Now that we have the Formula mass we can go ahead and do the calculation since we already have the Mass. You do as follows:

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