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iVinArrow [24]
3 years ago
9

QUESTION 1 A 2.5-g copper penny is given a charge of 4.0x10-9 C. If no more than one electron is removed from an atom, what perc

ent of the atoms are ionized by this charging process
Chemistry
1 answer:
wlad13 [49]3 years ago
7 0

Answer:

\%X=2.34*10^{-14}\%

Explanation:

From the question we are told that:

Mass M=2.5g

Charge q=4*0*10^{-9}

Generally the equation for Total number of Atoms in Penny is mathematically given by

 T_a=\frac{Mass}{atomic weight}*1mole

 T_a=\frac{2.5}{63.6}*6.02*10^{23}

 T_a=2.34*10^{27}atoms

Since Number of electrons in a penny is

 e =nT_a

 e=29*2.34*10^{27}

 e=6.86*10^{23}

Therefore

The percentage of the atoms are ionized by this charging process is given as

 \%X=\frac{T_a}{e}

 \%X=\frac{2.34*10^{27}}{6.86*10^{23}}

 \%X=2.34*10^{-14}\%

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