Question

QUESTION 1 A 2.5-g copper penny is given a charge of 4.0x10-9 C. If no more than one electron is removed from an atom, what percent of the atoms are ionized by this charging process

Answer 1

Answer:

$\%X=2.34*10^{-14}\%$

Explanation:

From the question we are told that:

Mass $M=2.5g$

Charge $q=4*0*10^{-9}$

Generally the equation for Total number of Atoms in Penny is mathematically given by

 $T_a=\frac{Mass}{atomic weight}*1mole$

 $T_a=\frac{2.5}{63.6}*6.02*10^{23}$

 $T_a=2.34*10^{27}atoms$

Since Number of electrons in a penny is

 $e =nT_a$

 $e=29*2.34*10^{27}$

 $e=6.86*10^{23}$

Therefore

The percentage of the atoms are ionized by this charging process is given as

 $\%X=\frac{T_a}{e}$

 $\%X=\frac{2.34*10^{27}}{6.86*10^{23}}$

 $\%X=2.34*10^{-14}\%$