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3 years ago

Electrical current in a wire

1 answer:

6 0

The electrical current in a wire could be from multiple things. This is how we wire our house. When the electrical current flows through the wire, it can power things like lights and appliances. The things that flow through a wire are called electrons.

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how much heat is lost when 71.07g of steam at 100 degrees condenses to form liquid water at 100 degrees

alukav5142 [94]

Answer:

Q = 160.36[kJ], is the heat lost.

Explanation:

This is a thermodynamic problem where we can find the latent heat of vaporization, at a constant temperature of 100 [°C].

We know that for steam at 100[C], the enthalpy is

$h_{gas} = 2675.6[kJ/kg]$

For liquid water at 100[C], the enthalpy is

$h_{water} = 419.17[kJ/kg]$

Therefore

$h_{g-w} = 2675.6-419.17 = 2256.43[\frac{kJ}{kg} ]$

The amout of heat is given by:

$Q=h_{g-w}*m\\ where:\\m = mass = 0.07107[kg] = 71.01[g]\\Q = heat [kJ]\\Q =2256.43*0.07107\\Q=160.36[kJ]$

3 0

3 years ago

1. Her angular speed increases because by pulling in her arms she creates a net torque in the direction of rotation. 2. Her angu

choli [55]

Answer:

3. Her angular speed increases because her angular momentum is the same but her moment of inertia decreases

Explanation:

II ωi the intial angular momentum of the skater. Her angular momentum changes to If ωf after pulling her arms in.

It must be noted that If is less than II, then it is because her arms now go round not far from the rotation axis which brings down the mementos of inertia.

Angular momentum does not change since torque is O.

Note: the mathematical representations are better written on the attached diagram.

5 0

4 years ago

Read 2 more answers

A particle executes simple harmonic motion with an amplitude of 2.00 cm. At what positions does its speed equal one fourth of it

White raven [17]

Answer:

The positions are 0.0194 m and - 0.0194 m.

Explanation:

Given;

amplitude of the simple harmonic motion, A = 2.0 cm = 0.02 m

speed of simple harmonic motion is given as;

$v = \omega \sqrt{A^2-x^2}$

the maximum speed of the simple harmonic motion is given as;

$v_{max} = \omega A$

when the speed equal one fourth of its maximum speed

$v =\frac{v_{max}}{4}$

$\omega\sqrt{A^2-x^2} = \frac{\omega A}{4} \\\\\sqrt{A^2-x^2}= \frac{A}{4}\\\\A^2-x^2 = \frac{A^2}{16} \\\\x^2 = A^2 - \frac{A^2}{16} \\\\x^2 = \frac{16A^2 - A^2}{16} \\\\x^2 = \frac{15A^2}{16} \\\\x= \sqrt{\frac{15A^2}{16} } \\\\x = \sqrt{\frac{15(0.02)^2}{16} }\\\\x = 0.0194 \ m \ \ or\ - 0.0194 \ m$

Thus, the positions are 0.0194 m and - 0.0194 m.

8 0

3 years ago

What do scientist use the H-R Diagram for and how do they use it?

Vanyuwa [196]

Answer:

The H-R diagram can be used by scientists to roughly measure how far away a star cluster or galaxy is from Earth. This can be done by comparing the apparent magnitudes of the stars in the cluster to the absolute magnitudes of stars with known distances (or of model stars).

7 0

3 years ago

Need help with Physics. 100 points + Brainliest

kiruha [24]

Answer:

I wrote down the answer and attached it below.

Explanation:

Hope this Helps!!!!

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8 0

3 years ago

Read 2 more answers