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Setler79 [48]
3 years ago
5

Is this right? plzz anwser soon

Physics
2 answers:
-Dominant- [34]3 years ago
6 0

Answer:

yes

Explanation:

Y_Kistochka [10]3 years ago
6 0

Answer:

y e p  

Explanation:

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alukav5142 [94]

Answer: a

Explanation: because i said so

8 0
2 years ago
Help please
pychu [463]
The answer should be speed hope this helps

3 0
3 years ago
Read 2 more answers
What average force is needed to accelerate a 7.00-gram pellet from rest to 155 m/s over a distance of 0.600 m along the barrel o
leonid [27]

Answer: The force needed is 140.22 Newtons.

Explanation:

The key assumption in this problem is that the acceleration is constant along the path of the barrel bringing the pellet from velocity 0 to 155 m/s. This means the velocity is linearly increasing in time.

The force exerted on the pellet is

F = m a

In order to calculate the acceleration, given the displacement d,  

d = \frac{1}{2}at^2\implies a=\frac{2d}{t^2}

we will need to determine the time t it took for the pellet to make the distance through the barrel of 0.6m. That time can be determined using the average velocity of the pellet while traveling through the barrel. Since the velocity is a linear function of time, as mentioned above, the average is easy to calculate as:

\overline{v}=\frac{1}{2}(v_{end}-v_{start})=\frac{1}{2}(155-0)\frac{m}{s}=77.5\frac{m}{s}

This value can be used to determine the time for the pellet through the barrel:

t = \frac{d}{\overline{v}}=\frac{0.6m}{77.5\frac{m}{s}}\approx0.00774s

Finally, we can use the above to calculate the force:

F = ma = m\frac{2d}{t^2} = 0.007kg\cdot \frac{2\cdot 0.6 m}{0.00774^2 s^2}\approx 140.22N



8 0
3 years ago
The temperature that sound moves through the air more quickly
Mademuasel [1]
Sound moves faster in warmer temperature because the particles move faster  
7 0
3 years ago
A string, 30 cm long and having a mass of 45 g, is attached to a 810 Hz oscillator at one end. The other end of the string is fi
Karolina [17]

Answer:

870 N

Explanation:

The expression for velocity of wave in a string is given below

v = \sqrt{\frac{T}{m} }  , T is tension and m is mass per unit length .

m = 45 x 10⁻³ / 30 x 10⁻²

= .15 kg/m

Putting the given values in the equation

76 = \sqrt{\frac{T}{.15} }

T = 76² x .15

= 866.4

870 N  approx.

3 0
3 years ago
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