Answer:
Vi = 94.64 m/s
Explanation:
I order to find out the initial velocity of the object, we can use third equation of motion:
2ah = Vf² - Vi²
where,
a = acceleration = -9.8 m/s²
h = maximum height covered by object = 460 m - 3 m = 457 m
Vf = Final Velocity = 0 m/s (since, object momentarily stops at highest point)
Vi = Initial Velocity = ?
Therefore,
2(-9.8 m/s²)(457 m) = (0 m/s)² - Vi²
Vi = √8957.2 m²/s²
<u>Vi = 94.64 m/s</u>
Im think its A. A release of a large amount 9f energy
Answer:
The answer is C. Steer in a straight line while gently slowing down
Explanation:
The following are advised when your cars go off the pavement while driving;
firstly, Do not panic.
ensure you hold on to your steering wheel tightly.
keep Steering straight ahead.
ensure you Stay on the shoulder.
Ease up on the accelerator and brake gently.
When you know you can safely do so, turn back on the road at a much lower speed.
Rhythms that occur faster and slower than the beat are b.<span>not synchronized with the time signature. The synchronization follows the same beat or rhythm. If the time signature say is lower than the original, then the rhythm should be faster. Otherwise, the rhythm is slower than the original one.</span>
