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Volgvan
3 years ago
10

The words bin and bean. rot and rat are examples of (blank)

Physics
1 answer:
Mariana [72]3 years ago
8 0

Answer:

the correct answer is homonyms

Explanation: Hope it helped

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An 16.00-kg object is suspended by a rope at some height, h if the object has a potential energy of 900.01j what is the objects
qwelly [4]

Answer:

5.740 m

Explanation:

PE = mgh

900.0 J = (16.00 kg) (9.8 m/s²) h

h = 5.740 m

5 0
2 years ago
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How does energy move through the atmosphere hydrosphere and biosphere
Anna11 [10]
<span>When the Sun’s energy moves through space, it reaches Earth’s atmosphere and finally the surface.  This radiant solar energy warms the atmosphere and becomes heat energy. This heat energy is transferred throughout the planet’s systems in three ways: by radiation, conduction, and convection</span>
5 0
2 years ago
You're collecting data in BeyondLabz for an object in free fall, subject to air resistance. How do you know when you've collecte
denis23 [38]

Enough data points would have been collected when specific data for upward and downward motion are collected.

<h3>What is a Data point?</h3>

A data point is a discrete unit of information. This information is always unique.

<h3>Free fall</h3>

An object subjected to free fall is under the influence of gravity. An object subjected has different time of motion for upward and downward motion.

Thus, we can conclude that enough data points would have been collected when specific data for upward and downward motion are collected.

Learn more about free fall here: brainly.com/question/10909077

6 0
2 years ago
4. Johnny exerts a 3.55 N rightward force on a 0.200-kg box to accelerate it across a low-friction track. If the total resistanc
Anon25 [30]

a) 15.2 m/s^2

b) 1.96 N

c) 1.96 N

Explanation:

a)

To find the box's acceleration, we have to find first the net force acting on the box in the horizontal direction.

We have:

- The forward force of 3.55 N

- The backward, resistive force of 0.52 N

So, the net force forward is

\sum F=3.55-0.52=3.03 N

Now we can find the acceleration by using Newton's second law of motion, which states that:

\sum F=ma

where

m = 0.200 kg is the mass of the box

a is its acceleration

And solving for a, we find the acceleration:

a=\frac{\sum F}{m}=\frac{3.03}{0.200}=15.2 m/s^2

b)

The gravitational force on an object is the force with which the object is pulled towards the ground by the Earth.

It is given by

W=mg

where

m is the mass of the object

g is the gravitational field strength

In this problem we have

m = 0.200 kg is the mass of the box

g=9.8 m/s^2 is the gravitational field strength

So, the gravitational force on the box is

W=(0.200)(9.8)=1.96 N

c)

The normal force is the reaction force exerted by the floor on the box, in the upward direction.

In order to find the magnitude of this force, we apply Newton's second law of motion along the vertical direction.

We have two forces in this direction:

- The gravitational force, W, downward

- The normal force, N, upward

So the net force is

\sum F=N-W

According to Newton's second law,

\sum F=ma

However, the box is at rest in the vertical direction, so the vertical acceleration is zero:

a=0

This means that the net force is zero:

\sum F=0

And so, we can find the normal force:

N-W=0\\N=W=1.96 N

4 0
2 years ago
a spring stretches by 0.12 m when some apples weighing 3.2 N are supported from it. What is the Spring Constant?
Rainbow [258]

Answer:

Fa==kx

ma=-kx

(3.2)(9.8)=-k(0.12)

k=27 N/M

8 0
3 years ago
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