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Olegator [25]
3 years ago
14

A precipitation reaction is caused by mixing 100. mL of 0.25 M K2Cr2O7 solution with 100. mL of 0.25 M Pb(NO3)2 solution. When t

he precipitate forms, it is filtered from the mixture.Which describes the changes in concentration of the spectator ions K+ and NO3- in the reaction mixture as the reaction occurs?K+ is doubled, NO3- halvedNeither is affectedK+ is halved, NO3- halvedBoth are doubled
Chemistry
1 answer:
Sergeeva-Olga [200]3 years ago
8 0

Answer:

Neither is affected

Explanation:

The reaction occurs as follows:

K₂Cr₂O₇ + Pb(NO₃)₂ → PbCr₂O₇ + 2K⁺ + 2NO₃⁻

That means per mole of reaction you will have two moles of both K⁺ and NO₃⁻.

But volume is also doubled, doing that concentration of spectator ions doesn't change.

Right answer: Neither is affected

I hope it helps!

You might be interested in
Round off each number to the indicated number significant figures (sf):
qaws [65]

Answer :

(a) The given number in 2 significant figures will be, 3.6\times 10^3

(b) The given number in 4 significant figures will be, 3.583\times 10^1

(c) The given number in 3 significant figures will be, 2.24\times 10^1

Explanation :

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

(a) The given number 00003554 converted into 2 significant figures.

In 00003554, there are 4 significant figures. Now we have to convert it into 2 significant figures.

The given number in 2 significant figures will be, 3.6\times 10^3

(b) The given number 35.8348 converted into 4 significant figures.

In 35.8348, there are 6 significant figures. Now we have to convert it into 4 significant figures.

The given number in 4 significant figures will be, 3.583\times 10^1

(c) The given number 22.4555 converted into 3 significant figures.

In 22.4555, there are 6 significant figures. Now we have to convert it into 3 significant figures.

The given number in 3 significant figures will be, 2.24\times 10^1

7 0
3 years ago
23) A common reaction that occurs in cells is shown here. In the presence of oxygen, a glucose molecule is combusted to form car
maw [93]

Answer:

C

Explanation:

add them together and multiply by 2

5 0
2 years ago
What are the rows of the periodic table called?
Gala2k [10]

Answer:

B. Groups

Explanation:

6 0
3 years ago
Read 2 more answers
A(n) _____ is a region where fresh water and salt water mix.
Airida [17]
It is called an estuary.
7 0
3 years ago
the quantity of antimony in an ore can be determined by an oxidation-reduction titration with an oxidizing agent. The ore is dis
Basile [38]

Answer:

BrO₃⁻(aq) + 3Sb³⁺(aq) + 6H⁺(aq) → Br⁻(aq) + 3Sb⁵⁺(aq) + 3H₂O(l)

Explanation:

At a redox equation, one substance is being oxidized (losing electrons), and the other is being reduced (gaining electrons). In the given reaction:

BrO₃⁻(aq) + Sb³⁺(aq) → Br⁻(aq) + Sb⁵⁺(aq)

When it's at an acidic solution, it must be ions H⁺ on the reactant, which will form water with the oxygen, so the complete reaction is:

BrO₃⁻(aq) + Sb³⁺(aq) + H⁺(aq) → Br⁻(aq) + Sb⁵⁺(aq) + H₂O(l)

As we can see, the antimony is being oxidized (go from +3 to +5), and the Bromo is being reduced. The oxidation number of brome in the reactant, knowing that the oxidation number of O is -2, is:

x + 3*(-2) = -1

x = +5

So, it's going from +5 to -1, and the half-reactions are:

BrO₃⁻(aq) + 6e⁻ → Br⁻(aq)

Sb³⁺(aq) → Sb⁵⁺(aq) + 2e⁻

The number of electrons must be the same, so the second equation must be multiplied by 3:

3Sb³⁺(aq) → 3Sb⁵⁺(aq) + 6e⁻

Thus, the equation will be:

BrO₃⁻(aq) + 3Sb³⁺(aq) + H⁺(aq) → Br⁻(aq) + 3Sb⁵⁺(aq) + H₂O(l)

Now, we verify the amount of the elements, which must be equal on both sides. So, we multiply H₂O by 3, and H⁺ by 6, and the balanced reaction will be:

BrO₃⁻(aq) + 3Sb³⁺(aq) + 6H⁺(aq) → Br⁻(aq) + 3Sb⁵⁺(aq) + 3H₂O(l)

6 0
3 years ago
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