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nikitadnepr [17]
2 years ago
14

Which concept can explain the acidic character of Carbon dioxide?​

Chemistry
2 answers:
Mamont248 [21]2 years ago
5 0

Answer:

The concept of lewis acids and bases can explain the acidic nature of CO2. A lewis acid is a compound which can accept an electron pair whereas a lewis base is a compound which can donate an electron pair. CO2 acts as a lewis acid.

BartSMP [9]2 years ago
3 0

Explanation:

Lewis acids and bases concept

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Kinetic energy is proportional to what
Kipish [7]

Answer:

mass and the square of the magnitude of velocity.

Explanation:

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2 years ago
The reactant side of a balanced chemical equation is shown below.
Sloan [31]

Answer:

2

Explanation:

In the equation, Cl is chlorine and there is a number "2" so that the correct answer is 2.

6 0
3 years ago
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One gram of Sn was electroplated from a SnCl, solution in 30 minutes. What was the current used?
Andrews [41]

Answer:

0.903 A

Explanation:

We have given mass of Sn = 1 gram

Time t=30 minutes=30×60=1800 sec

According to Faraday law m=zit

Where z is electron chemical equivalent

z is calculated by z=\frac{atomic\ mass}{nF} where n is number of element and F is Faraday constant

So z=\frac{atomic\ mass}{nF}=\frac{118.71}{2\times 96500}=0.000615

So 1=0.000615\times i\times 1800

i =0.903 A  

4 0
4 years ago
At what temperature would a 1.15 m NaCl solution freeze, given that the van't Hoff factor for NaCl is 1.9? Kf for water is 1.86
MariettaO [177]

Answer:

-4.1°C

Explanation:

The freezing-point depression (ΔTf) is a colligative property that can be calculated using the following expression:

ΔTf = i × Kf × m

where,

i: van't Hoff factor

Kf: freezing-point depression constant

m: molality

ΔTf = 1.9 × 1.86°C/m × 1.15 m = 4.1 °C

The freezing-point of pure water is 0°C. The freezing-point of this solution is:

0°C - 4.1°C = -4.1°C

8 0
4 years ago
Calculate the frequency of the green light emitted by a hydrogen atom with a wavelength of 546 nm.
Alona [7]

Answer: The frequency of the green light emitted by a hydrogen atom with a wavelength of 546 nm is 5.49 \times 10^{14} s^{-1}.

Explanation:

Given: Wavelength = 546 nm (1 nm = 10^{-9} m) = 546 \times 10^{-9} m

The relation between frequency and wavelength is as follows.

\nu = \frac{c}{\lambda}

where,

\nu = frequency

c = speed of light = 3.0 \times 10^{8} m/s

\lambda = wavelength

Substitute the values into above formula as follows.

\nu = \frac{c}{\lambda}\\= \frac{3.0 \times 10^{8} m/s}{546 \times 10^{-9} m}\\= 5.49 \times 10^{14} s^{-1}

Thus, we can conclude that the frequency of the green light emitted by a hydrogen atom with a wavelength of 546 nm is 5.49 \times 10^{14} s^{-1}.

4 0
3 years ago
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