Answer:
Soluable
Explanation:
Because salt dissolves in water.. Your question has no background information to go off of
Answer:
![\boxed {\tt 1.0 \ g/mL}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Ctt%201.0%20%5C%20g%2FmL%7D)
Explanation:
Density can be found by dividing the mass by the volume.
![d=\frac{m}{v}](https://tex.z-dn.net/?f=d%3D%5Cfrac%7Bm%7D%7Bv%7D)
The mass of the water is 50.0 grams.
The volume of the water is 50.0 milliliters.
![m= 50.0\ g \\v=50.0 \ mL](https://tex.z-dn.net/?f=m%3D%2050.0%5C%20g%20%5C%5Cv%3D50.0%20%5C%20mL)
Substitute the values into the formula.
![d=\frac{50.0 \ g}{50.0 \ mL}](https://tex.z-dn.net/?f=d%3D%5Cfrac%7B50.0%20%5C%20g%7D%7B50.0%20%5C%20mL%7D)
Divide.
![d= 1.0 \ g/mL](https://tex.z-dn.net/?f=d%3D%201.0%20%20%5C%20g%2FmL)
The density of the water is 1.0 grams per milliliter. Also, remember that the density of pure water is always 1.0 g/mL or g/cm³
Solution : As they have uniform composition throughout they are considered as homogeneous mixture. Both samples are mixture of two metals (gold and palladium) thus are alloys.
Answer:
![2CH_3COOH(aq)+Ba(OH)_2(aq)\rightarrow Ba(CH_3COO)_2(aq)+2H_2O(l)](https://tex.z-dn.net/?f=2CH_3COOH%28aq%29%2BBa%28OH%29_2%28aq%29%5Crightarrow%20Ba%28CH_3COO%29_2%28aq%29%2B2H_2O%28l%29)
Explanation:
When acetic acid solution and barium hydroxide solution react together to give an aqueous solution of barium acetate and water
The balanced chemical reaction will be given by
![2CH_3COOH(aq)+Ba(OH)_2(aq)\rightarrow Ba(CH_3COO)_2(aq)+2H_2O(l)](https://tex.z-dn.net/?f=2CH_3COOH%28aq%29%2BBa%28OH%29_2%28aq%29%5Crightarrow%20Ba%28CH_3COO%29_2%28aq%29%2B2H_2O%28l%29)
Answer: It's equal to 10^(-2.3), or 0.00501 M, or 5.01 * 10^-3 moles/Liter
Explanation:
Well, pH = - log[H+]
Or, in words, pH is equal to -1 multiplied by the logarithm (base 10) of the hydrogen ion concentration.
So you have 2.3 = -log[H+]. We want to isolate the H+, so let's start simplifying the right hand side of the equation. First, we multiply both sides by -1.
-2.3=log[H+]
Now, the definition of a logarithm says that if the log (base 10) of [H+] is -2.3, then 10 raised to the -2.3 power is [H+]
So on each side of the equation, we raise 10 to the power of that side of the equation.
10^(-2.3) = 10^(log[H+])
and because 10^log cancels out...
10^(-2.3) = [H+]
Now we've solved for [H+], the hydrogen ion concentration!