An acid is an ionic compound that produces positive hydrogen ions when dissolved in water. Acids taste sour and turn blue litmus paper red. A base is an ionic compound that produces negative hydroxide ions when dissolved in water. Bases taste bitter and turn red litmus paper blue.
Answer:
Explanation:
In theory, not much of anything. The vast majority of nitrates are water soluble. Aside, not sure what chemistry level you are at but you will probably be asked to know or memorize some solubility rules. This, for lack of a better phrase, Nitrate rule, is near spot on. With one exception—a rare one—all metal cationic nitrates are soluble in water. All of them. So, assuming you are talking about aqueous, water-based solutions of these salts and mixing them together, I expect nothing to occur. Both solutions, I believe are colorless in water and will thus remain so. If you had say a solution of Iron (III) nitrate and copper (II) nitrate, slightly different story. Both are colorful solutions and I would think you might see blending of colors but no reaction; no precipitate will form. You will probably learn about markers of a chemical reaction. One of these is a color change. Note, you should read this as a change of color from what you previously had. Going from red to blue or colorless to colored (or vice versa) is a strong indication of a reaction (e. g. evidence of bond-breaking and bond-formation). The mere mixing of colors does not constitute a chemical reaction.
The answer is D :) have a nice day!
Answer:: Ionic solutions completely dissociate into ions. i.e. NaCl becomes Na+ and Cl-.
Molecular compound donot dissociate, they remain whole compounds. i.e. CH2O remains CH2O.
Explanation:
Answer is: BaCO₃ (barium carbonate).
barium carbonate is white powder with low solubility in water, but good solubility in acids (<span>with the exception of sulfuric acid), because it forms solunle salts and carbonic acid (decomposes on carbon(IV) oxide and water).
For example if we add hydrochloric acid in barium carbonate:
BaCO</span>₃(s) + 2HCl(aq) → BaCl₂(aq) + H₂CO₃(aq).
