It would be Sulfur Dioxide.
Like CO2. C is the Carbon and O2 is Dioxide and it equals Carbon Dioxide.
I hope this is a successful answer.
Answer:
The molar solubility of SrCO3 will be lower in 0.10 M 0 M Sr(NO3)2 because of Sr2+
Explanation:
The question reflects the phenomenon known in chemistry as common ion effect. Common ion effect refers to the decreased solubility of a solid in a solution that contains an ion in common with the solute.
In the case of our example here, both strontium carbonate and strontium nitrate possess the strontium II ion in common. The presence of this ion in strontium nitrate will decrease the solubility of strontium carbonate in accordance with Le Chateliers principle. Hence the answer.
The volume (in mL) of 0.242 M NaOH solution needed for the titration reaction is 39.44 mL
<h3>Balanced equation </h3>
CH₃CH₂COOH + NaOH —> CH₃CH₂COONa + H₂O
From the balanced equation above,
- The mole ratio of the acid, CH₃CH₂COOH (nA) = 1
- The mole ratio of the base, NaOH (nB) = 1
<h3>How to determine the volume of NaOH</h3>
- Volume of acid, CH₃CH₂COOH (Va) = 46.79 mL
- Molarity of acid, CH₃CH₂COOH (Ma) = 0.204 M
- Molarity of base, NaOH (Mb) = 0.242 M
- Volume of base, KOH (Vb) =?
MaVa / MbVb = nA / nB
(0.204 × 46.79) / (0.242 × Vb) = 1
Cross multiply
0.242 × Vb = 0.204 × 46.79
Divide both side by 0.242
Vb = (0.204 × 46.79) / 0.242
Vb = 39.44 mL
Thus, the volume of NaOH needed for the reaction is 39.44 mL
Learn more about titration:
brainly.com/question/14356286
The one you have selected is correct. CO is a compound because it contains more than one element.
