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3 years ago

Which of the following diagrams correctly shows the reaction pathway of a reaction that releases energy ?

Chemistry

2 answers:

Zanzabum3 years ago

8 0

The answer is diagram A

zavuch27 [327]3 years ago

3 0

The answer is diagram A.

Hope this helped. Good luck!

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If the solution containing the metal complex ion is made acidic, why will the silver chloride precipitate

Ne4ueva [31]

Answer,

For example, silver ion can be precipitated with hydrochloric acid to yield solid silver chloride. Because many cations will not react with hydrochloric acid in this way, this simple reaction can be used to separate ions that form insoluble chlorides from those that do not.

7 0

2 years ago

Which energy resource causes the greatest waste disposal concerns?

Alex_Xolod [135]

Coal produces more pollution than any other energy source

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3 years ago

A reaction A(aq)+B(aq)↽−−⇀C(aq) has a standard free‑energy change of −4.20 kJ/mol at 25 °C. What are the concentrations of A, B,

Dafna1 [17]

Answer : The concentration of $A,B\text{ and }C$ at equilibrium are 0.132 M, 0.232 M and 0.168 M respectively.

Explanation :

The given chemical reaction is,

$A(aq)+B(aq)\rightleftharpoons C(aq)$

First we have to calculate the equilibrium constant for the reaction.

The relation between the equilibrium constant and standard free‑energy is:

$\Delta G^o=-RT \ln k$

where,

$\Delta G^o$ = standard free‑energy change = -4.20 kJ/mole

R = universal gas constant = 8.314 J/mole.K

k = equilibrium constant = ?

T = temperature = $25^oC=273+25=298K$

Now put all the given values in the above relation, we get:

$-4.20kJ/mole=-(8.314J/mole.K)\times (298K) \ln k$

$k=5.45$

Now we have to calculate the concentrations of A, B, and C at equilibrium.

The given equilibrium reaction is,

$A(aq)+B(aq)\rightleftharpoons C(aq)$

Initially 0.30 0.40 0

At equilibrium (0.30-x) (0.40-x) x

The expression of equilibrium constant will be,

$k=\frac{[C]}{[A][B]}$

$5.45=\frac{x}{(0.30-x)\times (0.40-x)}$

By solving the term x, we get

$x=0.168\text{ and }0.716$

From the values of 'x' we conclude that, x = 0.716 can not more than initial concentration. So, the value of 'x' which is equal to 0.716 is not consider.

The value of x will be, 0.168 M

The concentration of $A$ at equilibrium = (0.30-x) = 0.30 - 0.168 = 0.132 M

The concentration of $B$ at equilibrium = (0.40-x) = 0.40 - 0.168 = 0.232 M

The concentration of $C$ at equilibrium = x = 0.168 M

3 0

4 years ago

An ice-skating rink has tubes under its floor to freeze the water. salt water is cooled well below the freezing point of water a

alex41 [277]

Correct Answer: Option g: adding salt to water lowers its freezing point

Reason:
Freezing point is a colligative property. When a non-volatile solution is present in solution, it's freezing point decreases. This is referred as depression in freezing point (ΔTf). Extent of lowering in freezing point is dependent on number of particles present in system. Mathematically it is expressed as:

ΔTf = Kf X m

where, m = molality of solution
Kf = cryoscopic constant.

Hence, adding salt to water lowers the freezing point of solution.

6 0

3 years ago

Which of the following molecules nonpolar?

kap26 [50]

Answer:

CHC13

Explanation:

4 0

4 years ago