Answer:
a) K = 5.3175
b) ΔG = 3.2694
Explanation:
a) ΔG° = - RT Ln K
∴ T = 25°C ≅ 298 K
∴ R = 8.314 E-3 KJ/K.mol
∴ ΔG° = - 4.140 KJ/mol
⇒ Ln K = - ( ΔG° ) / RT
⇒ Ln K = - ( -4.140 KJ/mol ) / (( 8.314 E-3 KJ/K.mol )( 298 K ))
⇒ Ln K = 1.671
⇒ K = 5.3175
b) A → B
∴ T = 37°C = 310 K
∴ [A] = 1.6 M
∴ [B] = 0.45 M
∴ K = [B] / [A]
⇒ K = (0.45 M)/(1.6 M)
⇒ K = 0.28125
⇒ Ln K = - 1.2685
∴ ΔG = - RT Ln K
⇒ ΔG = - ( 8.314 E-3 KJ/K.mol )( 310 K )( - 1.2685 )
⇒ ΔG = 3.2694
I’m pretty sure it would be B
Answer: 1.91 moles
Explanation:
First you want to find the molar mass of NaCL
Na = 22.99g Cl = 35.45g
22.99g + 35.45g = 54.44g
Then divide 111.5g by 54.44g and this will give you moles.
Answer:
C
Explanation:
They are stabil and full of valence electron.
Answer:
The functional group present in Cinnamon are : Aromatic , alkene , aldehyde
The functional group present in Almonds : Aromatic , aldehyde
The functional group present in DHA : Ketone , alcohol
Explanation:
<u>Almond :</u>
Chemical formula : 
It contain : A benzene ring (Aromatic) , a -CHO group (aldehyde)
<u>Cinnamon Sticks</u> :
Chemical Formula : 
It contain : A benzene ring (Aromatic) ,an alkene group (C=C) , a -CHO group (aldehyde)
<u> </u><u>DHA:</u>
Chemical Formula : 
It contain : Alcohol group (-OH) , ketone group (C=O)