if the temperature of 20.0 L of gas were increased to twice the initial value, while the pressure is held constant what would be
1 answer:
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pH of 0.048 M HClO is 4.35.
<u>Explanation:</u>
HClO is a weak acid and it is dissociated as,
HClO ⇄ H⁺ + ClO⁻
We can write the equilibrium expression as,
Ka =
Ka = 4.0 × 10⁻⁸ M
4.0 × 10⁻⁸ M =
Now we can find x by rewriting the equation as,
x² = 4.0 × 10⁻⁸ × 0.048
= 1.92 × 10⁻⁹
Taking sqrt on both sides, we will get,
x = [H⁺] = 4.38 × 10⁻⁵
pH = -log₁₀[H⁺]
= - log₁₀[ 4.38 × 10⁻⁵]
= 4.35
Answer: M = 2.08 M
Explanation: Molarity is expressed as the number of moles per unit volume in liters. First convert the mass of HCl to moles using its molar mass. Then substitute the variables to the formula for molarity.
75.00 g HCl x 1 mole HCl / 36 g HCl
= 2.08 moles HCl
For Molarity.
M = n / L
= 2.08 moles HCl / 1.000 L
= 2.08 M
