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Cloud [144]
3 years ago
6

if the temperature of 20.0 L of gas were increased to twice the initial value, while the pressure is held constant what would be

the volume of the gas at the new temperature
Chemistry
1 answer:
Kay [80]3 years ago
7 0

Answer:

40 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 20 L

Initial temperature (T₁) = T

Final temperature (T₂) = 2T

Pressure (P) = constant

Final volume (V₂) =?

The new (i.e final) volume of the gas can be obtained as follow:

V₁/T₁ = V₂/T₂

20/T = V₂/2T

Cross multiply

T × V₂ = 20 × 2T

T × V₂ = 40T

Divide both side by T

V₂ = 40T /T

V₂ = 40 L

Therefore, the new volume of the gas is 40 L

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How many electrons are there in an atom of carbon?​
Mashutka [201]

Answer:

if its a neutral atom there should be 6 electrons because there are 6 protons

Explanation:

8 0
3 years ago
How many molecules of carbon dioxide are in 9.080 x 10 ^-1 mol?
kakasveta [241]

Answer:

5.46 8 x 10²³ molecules.

Explanation:

  • <em>Knowing that every one mole of a substance contains Avogadro's no. of molecules (NA = 6.022 x 10²³).</em>

<em><u>Using cross multiplication:</u></em>

1.0 mole → 6.022 x 10²³ molecules.

9.08 x 10⁻¹ mole → ??? molecules.

∴ The no. of molecules of CO₂ are in 9.08 x 10⁻¹ mol = (6.022 x 10²³ molecules) ( 9.08 x 10⁻¹ mole) / (1.0 mol) = 5.46 8 x 10²³ molecules.

6 0
3 years ago
How many Ne atoms are contained in 32.0 g of the element?
Svetlanka [38]
Mass atomic of Ne=20.18 u
Therefore:
molar mass=20.18 g/1 mol

1 mole=6.022*10²³ particles (atoms or molecules)

Then: 6.022*10²³ atoms are contained in 20.18g

Now, We can solve this problem by the three rule.

6.022*10²³ atoms-------------------20.18 g
x------------------------------------------32 g

x=(6.022*10²³ atoms * 32 g)/20.18 g=9.55*10²³ atoms.

Answer: 9.55*10²³ Ne atoms are contained in 32 g of the element.
3 0
3 years ago
What is the mass of H2O
Dovator [93]

Answer:

The exact molecular mass is 18.01528 g/mol

Explanation:

Find this by adding the molecular masses of two hydrogen atoms and one oxygen atom.

8 0
3 years ago
If a gas sample has a pressure of 30.7 kPa at 0.00*C, by how much does the temperature have to decrease to lower the pressure to
Scrat [10]

Answer:

                      252.68 K  or   -20.46 °C

Explanation:

                    According to Gay-Lussac's Law, "Pressure and Temperature at given volume are directly proportional to each other".

Mathematically,

                                              P₁ / T₁  =  P₂ / T₂   ---- (1)

Data Given:

                  P₁  =  30.7 kPa

                  T₁  =  0.00 °C  =  273.15 K

                  P₂  =  28.4 kPa

                  T₂  =  <u>???</u>

Solving equation for T₂,

                  T₂  =  P₂ T₁ / P₁

Putting values,

                  T₂  =  28.4 kPa × 273.15 K / 30.7 kPa

                  T₂  =  252.68 K  or   -20.46 °C

8 0
3 years ago
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