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True [87]
4 years ago
7

Which line is perpendicular to y = 2x -8

Mathematics
2 answers:
zlopas [31]4 years ago
6 0
A- Perpendicular lines have negative reciprocal slopes. Therefore a perpendicular line to 2x-8 will have a slope of -1/2. Once solved in slope intercept form, choice A shows a line of slope -2/4, equivalent to -1/2
MissTica4 years ago
4 0

Answer:

Choice A is correct answer.

Step-by-step explanation:

We have to find a equation of line which is perpendicular to y=2x-8.

The slope of perpendicular lines are negative reciprocals of each other.

y=mx+c is standard form of equation of line where m is slope and c is y-intercept.

given equation is :

y=2x-8

Compare above equation with standard form of equation of line,we get

m=2

The slope of perpendicular lines are negative reciprocals of each other.

Hence,  m=-1/2

4y=-2x+2

dividing by 4 to both sides of above equation ,we get

Choice A is:

4y/4=-2x+2/4

y=-2/4x+2/4

y=-1/2x+1/2

hence,choice A has slope equal to -1/2.

4y=-2x+2 is equatio of line perpendicular to y=2x-8.

So,choice A is the answer.


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Circles (represented by their equations in general form) in ascending order of their radius lengths can be arranged as first-fifth-second-forth-third-seventh-sixth.

<h3>What is the equation of circle?</h3>

The equation of the circle is the equation which is used to represent the circle in the algebraic equation form with the value of center point in the coordinate plane and measure of radius.

The standard form of the equation of the circle can be given as,

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Lets arrange the first equation, in standard form of equation of circle as,

x^2 +y^2 - 2x+ 2y -1 = 0 \\(x^2 - 2x) +(y^2+ 2y )= 1\\(x^2 - 2x+1) +(y^2+ 2y +1)= 1+1+1\\(x-1)^2+(y+1)^2=(\sqrt{3})^2

The radius of this circle is √(3).

Lets arrange the second equation, in standard form of equation of circle as,

x^2 +y^2 - 4x+ 4y - 10 = 0  \\(x^2 - 4x) +(y^2+ 4y )= 10\\(x^2 - 4x+4) +(y^2+ 4y +4)= 10+4+4\\(x-2)^2+(y+2)^2=(\sqrt{18})^2

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Lets arrange the third equation, in standard form of equation of circle as,

x^2 +y^2 - 8x - 6y - 20 = 0   \\(x^2 - 8x) +(y^2-6y )= 20\\(x^2 - 8x+16) +(y^2- 6y +9)= 10+16+9\\(x-4)^2+(y-3)^2=(\sqrt{45})^2

The radius of this circle is √(45).

Similarly, radius of the forth, fifth, sixth and seventh circle is √(23), √(5), √(117) and √(46) units.

Hence, the circles (represented by their equations in general form) in ascending order of their radius lengths can be arranged as first-fifth-second-forth-third-seventh-sixth.

Learn more about the equation of circle here;

brainly.com/question/1506955

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an easier way to think of it is 21 divided by 3, which again, is 7.

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