Answer:
<u>The volume of the cone is 1,102.7 feet³ (cubic)</u>
Step-by-step explanation:
1. Let's review the information given to us to answer the question correctly:
Radius = 9 feet
Height = 13 feet
2. What is the exact volume of the cone?
We will use the following formula to calculate the volume of the cone:
Volume of the cone = π * Radius² * Height/3
Volume of the cone = 3.1416 * 9² * 13/3
Volume of the cone = 3.1416 * 81 * 13/3
Volume of the cone = 3.1416 *9² * 13/3
<u>Volume of the cone = 1,102.7 feet³ (cubic)</u>
Answer:
Dr Carter
Step-by-step explanation:
I would want to visit Dr. Carter for an orthodontis appointment for multiple reasons. One, he can prove that he doesn’t do his work sloppily as his office is clean, and two, he can prove that his treatments work. since his teeth are now perfectly straight, that shows that his Braces really work, whereas Dr. Shuman’s treatments either don’t work or take a lot longer for results to appear.
Answer:
25 in x 15 in
Step-by-step explanation:
Given:
- Length = 3/5 the width
- Area = 375 in²
Let width = 
Therefore, length = 3/5 
First create an equation for the area of the picture based on the given information for its width and length:

We are told the area of the enlarged picture is 375 in². Therefore, substitute this into the equation and solve for
to find the width of the enlarged picture:

Therefore, the width of the enlarged picture is 25 in.
Substitute the found value of
into the expression for length to find the length of the enlarged picture:

Therefore, the dimensions of the enlarged picture are <u>25 in x 15 in</u>. The width is 25 in and the length is 15 in, as the length is 3/5 of the width.
1/10 4/5 we need common denominaters so
1/10 4(2)/(5)= 8/10
Answer:
6 + 3 (-8 x -2)
Step-by-step explanation:
6 + 3 (-8 x -2)
= 6+3 ( 16 )
= 9 ( 16 )
= 144