Area of a rectangle of length L and width W is A = LW.
Here, A = 60 ft^2 = (12 ft)(2x-3 ft). Let's find the values of x for which the area =60 ft^2, and then the values of x for which the area is greater than 60 ft^2.
60 = 12(2x-3) becomes 5 = 2x - 3 after dividing both sides by 12.
Adding 3 to both sides of this last equation results in 8 = 2x, so x = 4.
Does (12 ft)(2[4 ft] - 3) = 60? Does (12 ft)(5 ft) = 60 sq ft? YES.
The area of this rectangle will be greater than 60 sq ft if x>4 ft. (answer)
Answer:
25.5
Step-by-step explanation:
3 large necklaces equals 20.4 plus 5.10 equals 25.5
Answer:
D. 10 x 6/2
Step-by-step explanation:
each row = 6/2
10 rows all together
so you do 10 x 6/2
The table is attached as a figure
The given equation is ⇒⇒⇒⇒ y = 2x
To solve this equation, we need to pick numbers from the table then this number will be substituted into the equation to find y
we need 3 solutions . so, we need to pick 3 numbers of x
From the table, let us choose x = 0
y = 2x
y = 2 * (0)
y = 0
From the table, let choose second value of x such as x = 1
y = 2 * (1)
y = 2
From the table, let choose third value of x such as x = -1
y = 2 * (-1)
y = -2
So, the picked three solutions are y = 0 at x = 0y = -2 at x = -1y = 2 at x = 1
Factor the Polynomial by solving x^2 + bx + c = 0.
m^2 - mv - 56v^2
Factor by grouping.
(m−8v)(m+7v).
x^2 + bx + c = 0
