<h3>
Answer:</h3>
87.02%
<h3>
Explanation:</h3>
Percent yield of a product in a chemical equation is the ratio of actual or experimental yield to theoretical yield expressed as percentage.
In this case we are given;
Mass of Zinc as 7.23 g
Actual volume of Hydrogen gas produced as 2.16 L
We are required to calculate the percentage yield of Hydrogen gas;
<h3>Step 1: Write a balanced equation for the reaction</h3>
The balanced equation for the reaction between Zinc metal and Hydrochloric acid is given by;
Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g)
<h3 /><h3>Step 2: Moles of Zinc metal that reacted </h3>
Moles are given by dividing mass with molar mass
Moles = Mass ÷ Molar mass
Molar mass of Zinc = 65.38 g/mol
Therefore;
Number of moles = 7.23 g ÷ 65.38 g/mol
= 0.1106 moles
<h3>Step 3: Calculate the number of moles of Hydrogen gas produced</h3>
From the equation 1 mole of Zinc results in the formation of 1 mole of Hydrogen gas.
Therefore, Moles of hydrogen gas = Moles of Zinc × 1
= 0.1106 moles × 1
= 0.1106 moles
<h3>Step 4: Calculate the theoretical volume of Hydrogen gas produced.</h3>
At STP, 1 mole of a gas occupies 22.4 Liters
Therefore;
Volume of Hydrogen = Number of moles × 22.4 L
= 0.1106 mole × 22.4 L
= 2.477 L
<h3>Step 5: Calculate the percent yield </h3>
Percent yield = (Actual yield ÷ Theoretical Yield) × 100%
= (2.16 L ÷ 2.477 L)× 100%
= 87.20%
Thus, the percent yield of hydrogen gas produced is 87.02%
