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SSSSS [86.1K]
3 years ago
15

PLSS HELP ASAP it's due

Chemistry
1 answer:
BartSMP [9]3 years ago
8 0
<h3>Answer:</h3>

87.02%

<h3>Explanation:</h3>

Percent yield of a product in a chemical equation is the ratio of actual or experimental yield to theoretical yield expressed as percentage.

In this case we are given;

Mass of Zinc as 7.23 g

Actual volume of Hydrogen gas produced as 2.16 L

We are required to calculate the percentage yield of Hydrogen gas;

<h3>Step 1: Write a balanced equation for the reaction</h3>

The balanced equation for the reaction between Zinc metal and Hydrochloric acid is given by;

Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g)

<h3 /><h3>Step 2: Moles of Zinc metal that reacted </h3>

Moles are given by dividing mass with molar mass

Moles = Mass ÷ Molar mass

Molar mass of Zinc = 65.38 g/mol

Therefore;

Number of moles = 7.23 g ÷ 65.38 g/mol

                             = 0.1106 moles

<h3>Step 3: Calculate the number of moles of Hydrogen gas produced</h3>

From the equation 1 mole of Zinc results in the formation of 1 mole of Hydrogen gas.

Therefore, Moles of hydrogen gas = Moles of Zinc × 1

                                                         = 0.1106 moles × 1

                                                         = 0.1106 moles

<h3>Step 4: Calculate the theoretical volume of Hydrogen gas produced.</h3>

At STP, 1 mole of a gas occupies 22.4 Liters

Therefore;

Volume of Hydrogen = Number of moles × 22.4 L

                                   = 0.1106 mole × 22.4 L

                                  = 2.477 L

<h3>Step 5: Calculate the percent yield </h3>

Percent yield = (Actual yield ÷ Theoretical Yield) × 100%

                      = (2.16 L ÷ 2.477 L)× 100%

                     = 87.20%

Thus, the percent yield of hydrogen gas produced is 87.02%

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The mole fraction of a non-electrolyte (MM 40.0 g/mol) in a saturated aqueous solution is 0.310. What is the molality of the sol
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<u>Answer:</u> The molality of non-electrolyte is 24.69 m

<u>Explanation:</u>

We are given:

Mole fraction of saturated aqueous solution = 0.310

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To calculate the mass from given number of moles, we use the equation:

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Putting values in above equation, we get:

0.690mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(0.690mol\times 18g/mol)=12.42g

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\text{Molality}=\frac{n_{solute}\times 1000}{W_{solvent}\text{ (in grams)}}

Where,

n_{solute} = Moles of solute (non-electrolyte) = 0.310 moles

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Putting values in above equation, we get:

\text{Molality of non-electrolyte}=\frac{0.310\times 1000}{12.42}\\\\\text{Molality of non-electrolyte}=24.96m

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Read 2 more answers
Diamond is forever" is one of the most successful advertising slogans of all time. but is it true? for the reaction shown below,
Zielflug [23.3K]

The given reaction is

C _{(Diamond)}\rightarrow C_{(Graphite)}

An element can exist in 2 or more different forms which have totally different chemical and physical properties. They are known an allotropes.

Diamond and Graphite are allotropic forms of carbon. In the given reaction, diamond is changing to graphite and we have to find out the standard free energy of this reaction. This will help us to find out whether this reaction is spontaneous at 298 K or not.

The following data is needed for calculations which is taken from standard reference table.

H_{f}^{0}(diamond)= 1.895 kJ/mol

H_{f}^{0}(graphite)= 0

S^{0}(diamond)=2.337 J/mol-K

S^{0}(graphite)=5.740 J/mol-K

Step 1: Find ΔH⁰ rxn for the given reaction.

The formula to calculate ΔH⁰ rxn is given below.

\bigtriangleup H^{0}_{rxn}= H_{f}(product)- H_{f}( reactant)

We have graphite on product side and diamond on reactant side.

Therefore, \bigtriangleup H^{0}_{rxn}= H_{f}(graphite)- H_{f}(diamond)

Let us plug in the values given above.

\bigtriangleup H^{0}_{rxn}= 0 - 1.895 kJ/mol

\bigtriangleup H^{0}_{rxn}=  - 1.895 kJ/mol

ΔH⁰ rxn for the given reaction is -1.895 kJ/mol

Step 2 : Find ΔS⁰ rxn for the given reaction.

The formula to calculate ΔS⁰ rxn is

\bigtriangleup S^{0}_{rxn}= S^{0}(product)- S^{0}( reactant)

\bigtriangleup S^{0}_{rxn}= S^{0}(graphite)- S^{0}(diamond)

\bigtriangleup S^{0}_{rxn}= (5.740J/mol.K) - (2.337 J/mol.K)

\bigtriangleup S^{0}_{rxn}= 3.403 J/mol.K

Let us convert this to kJ.

\frac{3.403J}{mol.K}\times \frac{1 kJ}{1000J}= 3.403\times 10^{-3}kJ/mol.K

ΔS⁰ rxn for the given reaction is 3.403 x 10⁻³ kJ/mol.K

Step 3: Find standard free energy ΔG⁰ rxn.

ΔG⁰ rxn for the given reaction is calculated as

\bigtriangleup G^{0}_{rxn}= \bigtriangleup H^{0}_{rxn}- T\times \bigtriangleup S^{0}_{rxn}

We have T = 298 K. Let us plug in the calculated values of ΔH⁰ rxn and ΔS⁰ rxn.

\bigtriangleup G^{0}_{rxn}= - 1.895 kJ/mol - [(298K)\times 3.403\times 10^{-3}kJ/mol.K]

\bigtriangleup G^{0}_{rxn}= - 1.895 kJ/mol - [1.014 kJ/mol]

\bigtriangleup G^{0}_{rxn}= - 2.909 kJ/mol

The standard free energy change for the given reaction is -2.909 kJ/mol

The negative value of delta G⁰ suggests that the given reaction is spontaneous at room temperature. That means diamond will slowly convert to graphite. The speed of this reaction is extremely slow, but yet the reaction is taking place. So over a period of time diamond will become graphite.

Therefore "Diamond is forever" is not true as it is going to get converted to graphite.

7 0
3 years ago
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