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SSSSS [86.1K]
3 years ago
15

PLSS HELP ASAP it's due

Chemistry
1 answer:
BartSMP [9]3 years ago
8 0
<h3>Answer:</h3>

87.02%

<h3>Explanation:</h3>

Percent yield of a product in a chemical equation is the ratio of actual or experimental yield to theoretical yield expressed as percentage.

In this case we are given;

Mass of Zinc as 7.23 g

Actual volume of Hydrogen gas produced as 2.16 L

We are required to calculate the percentage yield of Hydrogen gas;

<h3>Step 1: Write a balanced equation for the reaction</h3>

The balanced equation for the reaction between Zinc metal and Hydrochloric acid is given by;

Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g)

<h3 /><h3>Step 2: Moles of Zinc metal that reacted </h3>

Moles are given by dividing mass with molar mass

Moles = Mass ÷ Molar mass

Molar mass of Zinc = 65.38 g/mol

Therefore;

Number of moles = 7.23 g ÷ 65.38 g/mol

                             = 0.1106 moles

<h3>Step 3: Calculate the number of moles of Hydrogen gas produced</h3>

From the equation 1 mole of Zinc results in the formation of 1 mole of Hydrogen gas.

Therefore, Moles of hydrogen gas = Moles of Zinc × 1

                                                         = 0.1106 moles × 1

                                                         = 0.1106 moles

<h3>Step 4: Calculate the theoretical volume of Hydrogen gas produced.</h3>

At STP, 1 mole of a gas occupies 22.4 Liters

Therefore;

Volume of Hydrogen = Number of moles × 22.4 L

                                   = 0.1106 mole × 22.4 L

                                  = 2.477 L

<h3>Step 5: Calculate the percent yield </h3>

Percent yield = (Actual yield ÷ Theoretical Yield) × 100%

                      = (2.16 L ÷ 2.477 L)× 100%

                     = 87.20%

Thus, the percent yield of hydrogen gas produced is 87.02%

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Aliun [14]

The fraction of acetic acid that is dissociated is 0.18

Why?

The chemical equation for the dissociation of acetic acid (HAc) is the following:

HAc(aq) + H₂O(l) ⇄ H₃O⁺(aq) + Ac⁻(aq)

To find the fraction of acetic acid that is in the dissociated form (f), we apply the following equation (Ka for acetic acid is 1.76*10⁻⁵). This equation comes from solving the equation of the equilibrium constant for the dissociated fraction of HAc:

f=\frac{-Ka+\sqrt{Ka^{2} +4KaC} }{2C} = 0.18

Have a nice day!

#LearnwithBrainly

6 0
3 years ago
Hydrogen boils at 20k. what is the boiling point of hydrogen on the celsius scale
Dimas [21]

Celsius scale is related to kelvin scale by the following equation,

⁰C = K-273

°C = K-273  

So as here temperature is given in kelvin, so it can be converted into celsius as follows:

So 20 K = 20K-273 °C  

= -253 °C .

So, the 20 K temperature equals to -253 °C.

So , -253 °C is equals to  20 K or 20 K temperature equals to -253 °C.

4 0
3 years ago
What is the solubility product (or ion-product), Ksp, expression at equilibrium for calcium phosphate, Ca3(PO4)2?
Gnoma [55]

Answer : The expression for solubility constant for this reaction will be,

K_{sp}=[Ca^{2+}]^3[PO_4^{3-}]^2

Explanation :

Solubility product : It is defined as the product of the concentration of the ions  that present in a solution raised to the power by its stoichiometric coefficient in a solution of a salt. This takes place at equilibrium only.

The solubility product constant is represented as, K__{sp}.

The dissociation of calcium phosphate is written as:

Ca_3(PO_4)_2\rightleftharpoons 3Ca^{2+}+2PO_4^{3-}

The expression for solubility constant for this reaction will be,

K_{sp}=[Ca^{2+}]^3[PO_4^{3-}]^2

4 0
3 years ago
Why are protists that are heterotrophs considered "animal-like"? A they make their own food. B They don't need energy C They fee
goblinko [34]

Answer:

A, Animal-like protists are called protozoa. ... Like animals, they can move, and they are heterotrophs. That means they eat things outside of themselves instead of producing their own food

Explanation:

8 0
3 years ago
When heated, KClO3 decomposes into KCl and O2. 2KClO3⟶2KCl+3O2 If this reaction produced 13.2 g KCl, how many grams of O2 were p
MissTica

Answer:

8.5gm O2 produced

Explanation:

When heated, KClO3 decomposes into KCl and O2. 2KClO3⟶2KCl+3O2 If this reaction produced 13.2 g KCl, how many grams of O2 were produced?

for every 2 moles of KCl produced, 3 moles of O2 are produced

Mol weight of KCl =39+35.5=74.5gm

13.2 gm KCl = 13.2/74.5 = 0.177 moles

this will make (3/2) X 0.177 = 0.2655 moles of O2

O2 mol wt is 32  0.2655 X32 = 8.5gm O2 produced

7 0
2 years ago
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