26.4 kg of calcium hydroxide (Ca(OH)₂)
Explanation:
We have the following chemical reaction:
CaO + H₂O → Ca(OH)₂
molecular weight of Ca(OH)₂ = atomic mass of Ca × number of Ca atoms + atomic mass of O × number of O atoms + atomic mass of H × number of H atoms
molecular weight of Ca(OH)₂ = 40 × 1 + 16 × 2 + 1 × 2 = 74 g/mole
molecular weight of CaO = atomic mass of Ca × number of Ca atoms + atomic mass of O × number of O atoms
molecular weight of CaO = 40 + 16 = 56 g/mole
number of moles = mass / molecular weight
number of moles of CaO = 20 / 56 = 0.357 kmoles
Taking in account the chemical reaction we devise the following reasoning:
if 1 kmole of CaO produces 1 kmole of Ca(OH)₂
then 0.357 kmoles of CaO produces X kmoles of Ca(OH)₂
X = (0.357 × 1) / 1 = 0.357 kmoles of Ca(OH)₂
mass = number of moles × molecular weight
mass of Ca(OH)₂ = 0.357 × 74 = 26.4 kg
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number of moles
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Answer:
The answer to your question is: letter A
Explanation:
a.Strong electrical forces will make ionic compounds have high boiling points. This option is correct because ionic bonds are strong which makes substances have high boiling points.
b.Strong electrical forces will make ionic compounds have weak bonds. This option is false, ionic compounds have strong bonds.
c.A low amount of energy is needed to break the bonds in ionic compounds. The high amount of energy is needed to break ionic bonds.
d.Gravitational forces hold the bonds together in ionic compounds. Gravitational forces do not affect the ionic compounds.
The common way electrons are found in shells or orbitals that surround the nucleus of an atom.I hope it helped
The balanced chemical reaction for the substances given would be as follows:
Zn + 2HCl = ZnCl2 + H2
We are given the amounts of the reactants used in the reaction. We use these amounts to determine which is the limiting and excess reactant. We do as follows:
10 g Zn (1 mol / 65.38 g) = 0.1530 mol
10 g HCl (1 mol / 36.46 g) = 0.2743 mol
From the the stoichiometric ratio which is 1 is to 2, the limiting reactant would be hydrochloric acid and the excess would be zinc metal.
Mass of zinc that remains = 0.1530 - (0.2743 / 2) = 0.0159 g Zn
The answer would be D.
SiCl4 + 2H2O → SiO2 + 4HCl (balanced equation)