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Serga [27]
3 years ago
8

[A]a[B]b [C]c [D]d

Chemistry
1 answer:
svetlana [45]3 years ago
3 0

Answer:

Smaller; products; products  

Explanation:

aA  + bB ⇌ cC + dD

K_{\text{eq}} = \dfrac{\text{[C]}^{c}\text{[D]}^{d}}{\text{[A]}^{a}\text{[B ]}^{b}}\\\\\text{When the $K_{\text{eq}}$ is large, the number representing [A]$^{a}$[B ]$^{b}$ must be  $\textbf{smaller}$ than the}\\\text{number representing [C]$^{c}$[D]$^{d}$. This relationship means that the $\textbf{products}$ must be favoured}\\\text{and that the mixture at equilibrium is largely $\textbf{products}$.}

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The distance from the surface of the earth to the moon is approximately 3.8 * 10 to the 5th km. How many days would a distance l
Alla [95]

Answer:

82 days would take a distance like that, if we drive at 120 mi/h

Explanation:

Distance from Earth to moon is 3.8×10⁵ km

You drive at a speed of 120 mi/h

Let's convert the 120 mi/h to km/h

1 mi = 1.61 km

Then 120 mi . 1.61 km / 1mi = 193.2 km

New velocity is 193.2 km. Therefore,

193.2 km are driven in 1 hour

3.8×10⁵ km woul be driven in (3.8×10⁵ . 1)/ 193.2 = 1966.8 hours

1967 hours . 1 day / 24 hours = 82 days

5 0
4 years ago
a weather balloon contains 8.80 moles of helium at a ppressure of 0.992 atm and a temperature os 25 C at ground level. What is t
djverab [1.8K]
We can use the ideal gas law equation to find the volume of the balloon.
PV = nRT 
where 
P - pressure - 0.992 atm x 101 325 Pa/atm = 100 514 Pa
V - volume 
n - number of moles - 8.80 mol 
R - universal gas constant  - 8.314 Jmol⁻¹K⁻¹
T - temperature in kelvin - 25 °C + 273 = 298 K
Substituting these values in the equation 
100 514 Pa x V = 8.80 mol x  8.314 Jmol⁻¹K⁻¹ x 298 K
V = 217 L
volume of balloon is 217 L
7 0
3 years ago
What energy transformation is involved in movement of muscles
ki77a [65]
When muscles are moved this represents a transfer from chemical energy to mechanical energy. As always, energy is conserved in the system. Kinetic energy can then come from the mechanical energy.
3 0
3 years ago
How many moles of C are in a sample of C5H12 that also contains 22.5g of H?
pishuonlain [190]

The number of moles of C present in C₅H₁₂ that contains 22.5 g of H is 9.375 moles

<h3>How to determine the mass of C₅H₁₂ that contains 22.5 g of H</h3>

1 mole of C₅H₁₂ = (12×5) + (1×12) = 72 g

Mass of H in 1 mole of C₅H₁₂ = 12 × 1 = 12 g

Thus,

12 g of H is present in 72 g of C₅H₁₂

Therefore,

22.5 g of H will be present in = (22.5 × 72) / 12 = 135 g of C₅H₁₂

<h3>How to determine the mole of C present in 135 g of C₅H₁₂</h3>

72 g of C₅H₁₂ contains 5 moles of C

Therefore,

135 g of C₅H₁₂ will contain = (135 × 5) / 72 = 9.375 moles of C

Thus, 9.375 moles of C is present in C₅H₁₂ that contains 22.5 g of H

Learn more about mole:

brainly.com/question/13314627

#SPJ1

8 0
2 years ago
Tra số liệu trong sổ tay hóa học và vẽ đồ thị biểu diễn sự thay đổi của năng lượng ion hóa
kirza4 [7]

Explanation:

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fofifof

s

diwiwkw

3 0
3 years ago
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