The equilibrium constant of the reaction is 282. Option D
<h3>What is equilibrium constant?</h3>
The term equilibrium constant refers to the number that often depict how much the process is able to turn the reactants in to products. In other words, if the reactants are readily turned into products, then it follows that the equilibrium constant will be large and positive.
Concentration of bromine = 0.600 mol /1.000-L = 0.600 M
Concentration of iodine = 1.600 mol/1.000-L = 1.600M
In this case, we must set up the ICE table as shown;
Br2(g) + I2(g) ↔ 2IBr(g)
I 0.6 1.6 0
C -x -x +2x
E 0.6 - x 1.6 - x 1.190
If 2x = 1.190
x = 1.190/2
x = 0.595
The concentrations at equilibrium are;
[Br2] = 0.6 - 0.595 = 0.005
[I2] = 1.6 - 0.595 = 1.005
Hence;
Kc = [IBr]^2/[Br2] [I2]
Kc = ( 1.190)^2/(0.005) (1.005)
Kc = 282
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C)
Metallic solids consist of metal ions which are surrounded by delocalized electrons.
Answer: The capillary rise(h) in the glass tube is = 0.009m
Explanation:
Using the equation
h = 2Tcosθ/rpg
Given
Contact angle, θ = Zero
h = height of the glass tube=?
T = surface tension = 
r = radius of the tube = 0.1mm =0.0001m
p= density of ethanol = 
g= 
h = 
h= 0.09m
Therefore the capillary rise in the tube is 0.09m
Answer:
Copper is more reactive and higher in the activity series
Explanation:
Copper is able to replace the silver in a replacement reaction because it is more reactive and higher in the activity series.
Substances or ions that are higher in the activity series are typically more reactive than those ones below them.
In like manner, they are able to replace the lowers ones in a chemical reaction due to their higher reactivity potential.
A less reactive element and a lower one in the activity series cannot displace a higher one in the series.
Answer:
a) S = 0.0152 mol/L
b) S' = 4.734 g/L
Explanation:
S 2S S...............in the equilibrium
- Ksp = 1.4 E-5 = [ Ag+ ]² * [ SO42-]
a) molar solubility:
⇒ Ksp = ( 2S) ² * S = 1.4 E-5
⇒ 4S² * S = 1.4 E-5
⇒ S = ∛ ( 1.4 E-5 / 4 )
⇒ S = 0.0152 mol/L
b) solubility ( S' ) in grams per liter:
∴ Mw Ag2SO4 = 311.799 g/mol
⇒ S' = 0.0152 mol/L * ( 311.799 g/mol )
⇒ S' = 4.734 g/L