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dalvyx [7]
3 years ago
9

Tra số liệu trong sổ tay hóa học và vẽ đồ thị biểu diễn sự thay đổi của năng lượng ion hóa

Chemistry
1 answer:
kirza4 [7]3 years ago
3 0

Explanation:

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A geologist drew a diagram illustrating a section of a boundary between two
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pls complete your question

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4 years ago
Which of the following is the sun responsible for?
musickatia [10]

Answer:

Im pretty sure it is B. Earths temperature

Explanation:

3 0
3 years ago
An electrical heater is used to add 21.75 kJ of heat to aconstant-volume calorimeter. The temperature of the calorimeterincrease
AlexFokin [52]

Answer:

The molar heat of combustion for butanol is 2.7 *10³ kJ/mol

Explanation:

Step 1: Data given

Temperature change = 4.18 °C

mass of butanol = 3.00 grams

When butanol is burned Temperature change = 20.81 °C

Step 2: Calculate Ccalorimeter

Ccal = 21750J / 4.18 °C = 5203.35 J/ °C

Step 3: Calculate heat generated

Heat generated = 20.81 °C * 5203.35 J/°C = 108281.71 J = 108.28 kJ

Step 4: Calculate moles of butanol

Number of moles = mass / molar mass

Number of moles = 3 grams / 74.123 g/mol = 0.04 moles

Step 5: Calculate Molar heat of combustion

Molar heat of combustion = 108.28 kJ / 0.04 moles = 2707 kJ /mol

The molar heat of combustion for butanol is 2.7 *10³ kJ/mol

3 0
3 years ago
A total of 2.00 mol of a compound is allowed to react with water in a foam coffee cup and the reaction produces 126 gg of soluti
lina2011 [118]

Answer : The enthalpy of this reaction is, 0.975 kJ/mol

Explanation :

First we have to calculate the heat produced.

q=m\times c\times (T_2-T_1)

where,

q = heat produced = ?

m = mass of solution = 126 g

c = specific heat capacity of water = 4.18J/g^oC

T_1 = initial temperature = 21.00^oC

T_2 = final temperature = 24.70^oC

Now put all the given values in the above formula, we get:

q=126g\times 4.18J/g^oC\times (24.70-21.00)^oC

q=1948.716J=1.95kJ

Now we have to calculate the enthalpy of this reaction.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat released = 1.95 kJ

n = moles of compound = 2.00 mol

Now put all the given values in the above formula, we get:

\Delta H=\frac{1.95kJ}{2.00mole}

\Delta H=0.975kJ/mol

Thus, the enthalpy of this reaction is, 0.975 kJ/mol

4 0
3 years ago
a 49.2 g sample of solid iron was heated from 16.2c to 58.9c.what ws the energy change?solve for q(heat energy).iron has a speci
svet-max [94.6K]

Answer:

944.12 J

Explanation:

To solve for the energy change we use the equation Q=mc(Delta)t

Let's identify the variables we have:

m (mass) = 49.2 g

c (specific heat) = .4494

delta t (change in temp.) = final - initial = 58.9-16.2 = 42.7 degrees Celsius

Q= (49.2)(.4494)(42.7)

  = 944.12 J

5 0
3 years ago
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