The point of comparison when discussing the position of an object is the

Much of the pollution in out oceans comes from:

BabaBlast [244]

Answer:

c.) sewage and industrial waste

3 0

3 years ago

A hiker begins a trip by first walking 25.0 km southeast from her car. She stops and sets up her tent for the night. On the seco

Sunny_sXe [5.5K]

Answer:

(a)

$x_1=17.68km\\y_1=-17.68km\\x_2=20km\\y_2=34.64km$

(b) $r=41.32km$

$\alpha =24.23^o$

Explanation:

Let us take the north direction to be the positive y-axis and the east to be positive x-axis.

First day:

25.0 km southeast, which implies $45^o$ south of east. The y-component will be negative and the x-component will be positive.

$x_1=25cos45^o=17.68km$

$y_1=-25sin45^o=-17.68km$

Second day:

She starts off at the stopping point of last day. This time, both the y- and x-components are positive.

$x_2=40cos60^o=20km$

$y_2=40sin60^o=34.64km$

Therefore, total displacements:

$x=x_1+x_2=(17.68+20)km=37.68km$

$y=y_1+y_2=(-17.68+34.64)km=16.96km$

Magnitude of displacements,

$r=\sqrt{x^2+y^2}=41.32km$

Direction,

$\alpha =tan^{-1}(\frac{y}{x})=24.23^o$

6 0

3 years ago

Monochromatic light of wavelength, lambda, is traveling in air. The light then strikes a thin film having an index of refraction

kumpel [21]

Answer:

The correct option is H

Explanation:

From the question we are told that

The index of refraction of coating is $n_1$

The index of refraction of material is $n_2$

Generally the condition for constructive for a thin film interference is mathematically represented

$2 * t = [ m + \frac{1}{2}] \frac{\lambda}{n_1 }$

Here t represents the thickness

For minimum thickness m = 0

So

$2 * t =0 + \frac{1}{2}\frac{\lambda}{n_1 }$

=> $t =\frac{\lambda}{4n_1 }$

3 0

3 years ago

What is the sprinters output at 2.0 s, 4.0 s and 6.0 s?

kari74 [83]

A 59 kg sprinter, starting from rest, runs 47 m in 7.0 s at constant acceleration.?

What is the sprinter's power output at 2.0 s, 4.0 s, and 6.0 s?

Instantaneous Power is the force times velocity

P = Fv

Because the acceleration is constant, the force will be constant as well

F = ma

P = mav

for constant acceleration, the velocity at each time is found using

v = at

P = ma(at) = ma²t

find the acceleration using kinematic equation

s = ½at²

a = 2s/t²

a = 2(47) / 7.0²

a = 1.918 m/s²

P(2.0) = 59(1.918²)2.0 = 434.25 W = 0.43 kW

P(4.0) = 59(1.918²)4.0 = 868.51 W = 0.87 kW

P(6.0) = 59(1.918²)6.0 = 1302.76 W = 1.3 kW

I hope this helped.

5 0

3 years ago

A coil of 150 turns of wire is in the form of a circle of radius 7.5 cm, and sits in the center of a dipole magnet that produces

irga5000 [103]

Answer:

Current in the loop is 0.063 A

Explanation:

Number of turns in the coil N = 150

Radius of the circular loop r = 7.5 cm = 0.075 m

So area $A=\pi r^2=3.14\times 0.075^2=0.0176m^2$

Magnetic field B = 1.5 T

Maximum torque is given $\tau =0.25Nm$

We have to find current in the coil

Torque on circular coil in magnetic field is equal to

$\tau =BINA$

$0.25=1.5\times I\times 150\times 0.0176$

I = 0.063 A

7 0

3 years ago