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UkoKoshka [18]
3 years ago
11

The speed of light in water is 2.25 x 108 m/s. What is true about the index of refraction of water? A. It is less than 1. B. It

is more than 1. C. It is 0. D. It is equal to 1.
Physics
2 answers:
alexgriva [62]3 years ago
8 0
The answer is letter B. more then one. hope this helps!
guajiro [1.7K]3 years ago
4 0
Good afternoon!


We can see that \mathsf{2.25\times10^8\ \textless \ 3\times10^8 = c}

The index of refraction can be calculated as:

\mathsf{n = \dfrac{c}{v}}

As we noted, \mathsf{v \ \textless \  c} , and therefore:

\mathsf{\dfrac{v}{v} \ \textless \  \dfrac{c}{v}}\\ \\ \\ \mathsf{\dfrac{c}{v} \ \textgreater \  1}

Beccause n = c/v, we have:

n > 1

B - Is more than 1.
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Answer:

The magnitude of F₁ is 3.7 times of F₂

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v_{1}=\dfrac{3.0\times10^{3}}{3600}

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The force F₁is constant acceleration is also a constant.

F_{1}=ma_{1}

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Using formula of acceleration

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a_{1}=0.083\ m/s^2

Similarly,

F_{2}=ma_{2}

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F_{3}=F_{2}+F_{1}

ma_{3}=ma_{2}+ma_{1}

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a_{2}=0.305-0.083

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\dfrac{F_{1}}{F_{2}}=3.7

F_{1}=3.7F_{2}

Hence, The magnitude of F₁ is 3.7 times of F₂

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