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UkoKoshka [18]
3 years ago
11

The speed of light in water is 2.25 x 108 m/s. What is true about the index of refraction of water? A. It is less than 1. B. It

is more than 1. C. It is 0. D. It is equal to 1.
Physics
2 answers:
alexgriva [62]3 years ago
8 0
The answer is letter B. more then one. hope this helps!
guajiro [1.7K]3 years ago
4 0
Good afternoon!


We can see that \mathsf{2.25\times10^8\ \textless \ 3\times10^8 = c}

The index of refraction can be calculated as:

\mathsf{n = \dfrac{c}{v}}

As we noted, \mathsf{v \ \textless \  c} , and therefore:

\mathsf{\dfrac{v}{v} \ \textless \  \dfrac{c}{v}}\\ \\ \\ \mathsf{\dfrac{c}{v} \ \textgreater \  1}

Beccause n = c/v, we have:

n > 1

B - Is more than 1.
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A baseball has a mass of 0.145 kilograms, and a bowling ball has a mass of 6.8 kilograms. What is the gravitational force betwee
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Fg = (Gm₁m₂)/r²
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Read 2 more answers
Particle A and particle B are held together with a compressed spring between them. When they are released, the spring pushes the
yaroslaw [1]

Answer:

 K_a = 8,111 J

Explanation:

This is a collision exercise, let's define the system as formed by the two particles A and B, in this way the forces during the collision are internal and the moment is conserved

initial instant. Just before dropping the particles

          p₀ = 0

final moment

          p_f = m_a v_a + m_b v_b

          p₀ = p_f

          0 = m_a v_a + m_b v_b

tells us that

          m_a = 8 m_b

         

           0 = 8 m_b v_a + m_b v_b

           v_b = - 8 v_a                    (1)

indicate that the transfer is complete, therefore the kinematic energy is conserved

starting point

           Em₀ = K₀ = 73 J

final point. After separating the body

          Em_f = K_f = ½ m_a v_a² + ½ m_b v_b²

           K₀ = K_f

           73 = ½ m_a (v_a² + v_b² / 8)

           

we substitute equation 1

           73 = ½ m_a (v_a² + 8² v_a² / 8)

           73 = ½ m_a (9 v_a²)

           73/9 = ½ m_a (v_a²) = K_a

            K_a = 8,111 J

3 0
3 years ago
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