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Rama09 [41]
3 years ago
10

3. Two Metra trains approach each other on separate but parallel tracks. Train A has a speed of 90 km/ hr, train B has a speed o

f 80 km/ hr. Initially, the two trains are 2.71 km apart. How long will it take the two trains to meet?
a. Write two complete equations that describe the position of: Train A:
Train B:
c. At what exact time will train A and train B be at the same position?
d. At what position is train A when it meets train B?
e. How far has train B travelled in this time?

CAN SOMEONE PLEASE HELP ME I HAVE BEEN TRYING TO SOLVE FOR 5 HOURS AND I STILL DONT KNOW THE ANSWER
Physics
1 answer:
Elden [556K]3 years ago
8 0

Answer:he trains take 57.4 s to pass each other.

Two trains A and B move towards each other. Let A move along the positive x axis and B along the negative x axis.

therefore,

The relative velocity of the train A with respect to B is given by,

If the train B is assumed to be at rest, the train A would appear to move towards it with a speed of 170 km/h.

The trains are a distance d = 2.71 km apart.

Since speed is the distance traveled per unit time, the time taken by the trains to cross each other is given by,

Substitute 2.71 km for d and 170 km/h for

Express the time in seconds.

Thus, the trains cross each other in 57.4 s.

Explanation:

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Answer:

3.90 degrees

Explanation:

Let g= 9.81 m/s2. The gravity of the 30kg grocery cart is

W = mg = 30*9.81 = 294.3 N

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We can calculate the parallel one since it's the one that affects the force required to push up

F = WsinΘ

Since customer would not complain if the force is no more than 20N

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sin\theta = 20/294.3 = 0.068

\theta = sin^{-1}0.068 = 0.068 rad = 0.068*180/\pi \approx 3.90^0

So the ramp cannot be larger than 3.9 degrees

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See the explanation below

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