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Rama09 [41]
3 years ago
10

3. Two Metra trains approach each other on separate but parallel tracks. Train A has a speed of 90 km/ hr, train B has a speed o

f 80 km/ hr. Initially, the two trains are 2.71 km apart. How long will it take the two trains to meet?
a. Write two complete equations that describe the position of: Train A:
Train B:
c. At what exact time will train A and train B be at the same position?
d. At what position is train A when it meets train B?
e. How far has train B travelled in this time?

CAN SOMEONE PLEASE HELP ME I HAVE BEEN TRYING TO SOLVE FOR 5 HOURS AND I STILL DONT KNOW THE ANSWER
Physics
1 answer:
Elden [556K]3 years ago
8 0

Answer:he trains take 57.4 s to pass each other.

Two trains A and B move towards each other. Let A move along the positive x axis and B along the negative x axis.

therefore,

The relative velocity of the train A with respect to B is given by,

If the train B is assumed to be at rest, the train A would appear to move towards it with a speed of 170 km/h.

The trains are a distance d = 2.71 km apart.

Since speed is the distance traveled per unit time, the time taken by the trains to cross each other is given by,

Substitute 2.71 km for d and 170 km/h for

Express the time in seconds.

Thus, the trains cross each other in 57.4 s.

Explanation:

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The magnetizing current in a transformer is rich in 3rd harmonic. This is because harmonics are AC voltages and currents with frequencies that are generally higher. 
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3 years ago
An object is thrown directly upwards from the ground at a velocity of 9ms. Recalling that the acceleration due to gravity is −gm
olga55 [171]

Answer:

Explanation:

Given

Object is thrown with a velocity of u=9\ m/s

Acceleration due to gravity is -g (i.e. acting downward)

Vertical distance traveled by object is given by

v^2-u^2=2as  

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

at maximum height final velocity is zero

0-(9)^2=2\times (-g)\times (s)

s=\frac{81}{2g}=\frac{40.5}{g}\ m

time taken to reach maximum height

using

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0=9-gt

t=\frac{9}{g}\ s

6 0
3 years ago
An unmarked police car traveling a constant 95 km/h is passed by a speeder. Precisely 1.00 s after the speeder passes, the polic
Montano1993 [528]

Answer:

Speed of the speeder will be 28 m/sec

Explanation:

In first case police car is traveling with a speed of 90 km/hr

We can change 90 km/hr in m/sec

So 90km/hr=\frac{90\times 1000m}{3600sec}=25m/sec

Car is traveling for 1 sec with a constant speed so distance traveled in 1 sec = 25×1 = 25 m

After that car is accelerating with a=2m/sec^2 for 7 sec

So distance traveled by car in these 7 sec

S=ut+\frac{1}{2}at^2=25\times 7+\frac{1}{2}\times 2\times 7^2=224m

So total distance traveled by police car = 224 m

This distance is also same for speeder

Now let speeder is moving with constant velocity v

so 224=\left ( 1+7 \right )v

v = 28 m/sec

4 0
3 years ago
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Answer: 71.93 *10^3 N/C

Explanation: In order to calculate the electric field from long wire we have to use the Gaussian law, this is:

∫E*dr=Q inside/εo  Q inside is given by: λ*L then,

E*2*π*r*L=λ*L/εo

E= λ/(2*π*εo*r)= 4* 10^-6/(2*3.1415*8.85*10^-12*2 )= 71.93 * 10^3 N/C

6 0
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If an atom has an atomic number of 2, it will be stable with 2 electrons in its valence shell. Group of answer choices True Fals
torisob [31]

Answer: True

Explanation:

Atomic number is defined as the number of protons or the number of electrons that are present in an electrically neutral atom.

Atomic number = Number of protons = number of electrons = 2

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The electronic configuration will be 1s^2

As its duplet is already complete and it has noble gas configuration , it is stable with 2 valence electrons.

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