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Rama09 [41]
2 years ago
10

3. Two Metra trains approach each other on separate but parallel tracks. Train A has a speed of 90 km/ hr, train B has a speed o

f 80 km/ hr. Initially, the two trains are 2.71 km apart. How long will it take the two trains to meet?
a. Write two complete equations that describe the position of: Train A:
Train B:
c. At what exact time will train A and train B be at the same position?
d. At what position is train A when it meets train B?
e. How far has train B travelled in this time?

CAN SOMEONE PLEASE HELP ME I HAVE BEEN TRYING TO SOLVE FOR 5 HOURS AND I STILL DONT KNOW THE ANSWER
Physics
1 answer:
Elden [556K]2 years ago
8 0

Answer:he trains take 57.4 s to pass each other.

Two trains A and B move towards each other. Let A move along the positive x axis and B along the negative x axis.

therefore,

The relative velocity of the train A with respect to B is given by,

If the train B is assumed to be at rest, the train A would appear to move towards it with a speed of 170 km/h.

The trains are a distance d = 2.71 km apart.

Since speed is the distance traveled per unit time, the time taken by the trains to cross each other is given by,

Substitute 2.71 km for d and 170 km/h for

Express the time in seconds.

Thus, the trains cross each other in 57.4 s.

Explanation:

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640 x 2.9 = 1856mi
580 x 2.9 = 1682mi
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You could also calculate her average speed.  This is easy since it was divided in two equal time slices.  Average Speed = (640+580)/2 = 610mi/hr
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The period of the oscillations.T = 1.2042s

Opposition is the process of any quantity or measure fluctuating repeatedly about its equilibrium value throughout time. This process is referred to as oscillation. Oscillation, a periodic fluctuation of a substance, can also be described as alternating between two values or rotating around a central value.

Typically, the mathematical formula for the moment of inertia is

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The period of the oscillations.T = 1.2042s

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g At some point the road makes a right turn with a radius of 117 m. If the posted speed limit along this part of the highway is
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Answer:

Ф = 28.9°

Explanation:

given:

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required: angle Ф

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Ф = inv tan (25.1² / (117 * 9.8))

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