Answer:
The major difference is the capacity of both batteries. The AA battery has a higher capacity (a higher current) than the AAA battery.
Explanation:
The AA batteries and the AAA batteries are very similar in their voltage; both of them have 1.5 V.
The difference between these two batteries is their size and also the current that they have. The AAA battery is smaller than the AA battery, which means that the amount of electrochemical material is lower, so the AA battery has a higher capacity (a higher current) than the AAA battery. Generally, AA battery has 2400 mAh capacity and AAA battery has a capacity of 1000mAh; this means that AA battery has almost three times the capacity of an AAA battery.
Furthermore, the size of the AA battery makes it more common than the AAA battery and therefore has higher commercial demand.
I hope it helps you!
Answer:
Net force = 0.0191 N
T=0.00054 N.m
p=99.2 μC.cm
Explanation:
Given that
L= 6.2 cm
q₁= 16μC
q₂=1μC
E= 1174 N/C
We know that
F = q E
F₁ = q₁ E
F₁ = 0.018 N
F₂=q₂ E
F₂=0.0011 N
Net force = F₁+F₂
Net force = 0.0191 N
Torque ,T
T = (F₁-F₂) L/2
T = (0.018 - 0.0011 ) x 0.032
T=0.00054 N.m
Polarization ,p
p= q d
p= 16 x 6.2 μC.cm
p=99.2 μC.cm
Answer:
a) V = 6.52 10⁻⁵ V, b) Vb = 9.34 10⁻⁵ V
Explanation:
b) When using Gauss's law all the charge is considered concentrated in the inside of the sphere, for which the electrice field is
Q = 3.92 10⁻¹⁵ C
E = k Q / r²
Electric potential and electric field are related
E = - dV / dr
dV = - E dr
Vb-Va = - k Q (1 / rb -1 / ra)
Vb = - 8.99 10⁸ 3.92 10⁻¹⁵ 1 / 0.0377
Vb = 9.34 10⁻⁵ V
a) In this case we must know the electric field for the interior of the sphere, use Gauss's law, the charge inside is
ρ = Q / V
= ρ (4/3 π r³)
Ф = E A = Q_{int} /ε₀
E 4π r² = ρ 4/3 π r³ /ε₀
E = ρ r / 3ε₀
dV = ρ / 3ε₀ ∫ r dr
V = ρ / 3ε₀ r²
We evaluate between the center of the sphere V = 0 and the point R
V = ρ / 3ε₀ ½ (R²)
V = Q 3 / 4π R³ 3ε₀ (R²) = k Q 1 / 2R
V = 8.99 10⁸ 3.92 10⁻¹⁵ 1 / 0.027 2
V = 6.52 10⁻⁵ V
Work = force * distance
and newton*meters = Joule
In this case, work = 250N*50m = 12500 J
So the answer is D) 12,500 J
Answer:5m
Explanation:a=-10m/s (since it moved upwards against gravity)
V=0
U=10m/s
v2=u2+2as
0= 100-20s
20s=100
s=5m