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2 years ago

Evaluate each expression using the order of operations 35-14/2+8 to the power of 2

Mathematics

1 answer:

aleksley [76]2 years ago

7 0

Answer:

8 + 4 ÷ (-24) × (3) - 4 = 35

Step-by-step explanation:

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The isosceles triangle has a perimeter of 7.5 m.

shepuryov [24]

D) 2.1+2x=7.5

All the sides added together will equal the perimeter

7 0

3 years ago

Read 2 more answers

Chase is a high school basketball player. In a particular game, he made some free throws (worth one point each) and some two poi

MaRussiya [10]

Answer:

free throws = 6

2 points shots = 3

Step-by-step explanation:

To do this we will have 2 incognitas.

x = number of free throws

y = number of shots of 2 points

x(1) + y(2) = 12

he says he made twice as many free throws as 2 points

x = 2y

2y(1) + y(2) = 12

2y + 2y = 12

4y = 12

y = 12/4

y = 3

x = 2y

x = 2*3

x = 6

free throws = 6

2 points shots = 3

8 0

3 years ago

Read 2 more answers

In the circle below, suppose m VUX = 152° and mZUVW = 77º. Find the following.

bezimeni [28]

Given:

In the circle, $m(\overarc{VUX})=152^\circ$ and $m(\angle MUV)=77^\circ$ .

To find:

The following measures:

(a) $m\angle VUX$

(b) $m\angle UXW$

Solution:

According to the central angle theorem, the central angle is always twice of the subtended angle intercepted on the same same arc.

$m(VUX)=2\times m\angle VWX$

$152^\circ=2\times m\angle VWX$

$\dfrac{152^\circ}{2}=m\angle VWX$

$76^\circ=m\angle VWX$

In a cyclic quadrilateral, the opposite angles are supplementary angles.

UVWX is a cyclic quadrilateral. So,

$m\angle VUX+m\angle VWX=180^\circ$ [Opposite angles of a cyclic quadrilateral]

$m\angle VUX+76^\circ=180^\circ$

$m\angle VUX=180^\circ-76^\circ$

$m\angle VUX=104^\circ$

Now,

$m\angle UXW+m\angle UVW=180^\circ$ [Opposite angles of a cyclic quadrilateral]

$m\angle UXW+77^\circ =180^\circ$

$m\angle UXW=180^\circ-77^\circ$

$m\angle UXW=103^\circ$

Therefore, $m\angle VUX=104^\circ$ and $m\angle UXW=103^\circ$ .

7 0

3 years ago

Lee watches TV for 2 hours per day. During that time, the TV consumes 250 watts per hour. Electricity costs (10 cents)/(1 kilowa

vladimir1956 [14]

Answer:

$1.5

Step-by-step explanation:

Lets us first calculate energy consumed by TV in 30 days.

Energy consumed by TV in one hour : 250 watts.

TV operated 2 hours a day

so energy consumer by TV in a day = 250 * 2 watts = 500 watts hour

Energy consumed by TV in 30 day = energy consumer by TV in a day * 30

= 500*30 watts = 15,000 watt-hour

Convert total energy consumed in kilo watt hour

we know that one kilowatt hour = 1000 watt-hour

Thus, 15,000 watt-hour = 15,000/1000 kilowatt-hour = 15 kilowatt-hour

________________________________

cost of electricity = 10 cents per kilowatt-hour

cost of electricity for 15 kilowatt-hour = 15* cost of electricity for one kilowatt-hour( which is 10 cents)

=>15*10 = 150 cents

As $1 = 100 cents

hence 150 cents = $150/100 = $1.5 .

Thus, it cost $1.5 to to operate for a month of 30 days.

6 0

3 years ago

Pls help me divide this radical and pls show work

Alenkinab [10]

Let's start by rationalizing the radical:

4√6/√50 * √50/√50

This gets rid of the radical in the denominator, giving us:

4√300/50

√300 can be simplified to √3 * √100 or 10√3. Now we can insert this back into the numerator:

4 * 10√3/50

This is equivalent to:

40√3/50

40/50 can be simplified to 4/5.

Therefore, the answer is 4√3/5.

5 0

3 years ago