Step-by-step explanation:

In this method , the second order of polynomial ax² + bx + c is factorised and expressed as the product of two linear factors. Then each linear factor is separately solved to get the required solutions of the equation by applying zero factor property. In zero factor property , if p•q = 0 , then either p = 0 or q = 0 . In other words , if the product of two numbers is 0 , then one or both of the numbers must be 0.


Here , we have to find the two numbers that multiplies to 55 and adds to 16.
⤑ 
⤑ 
⤑ 
⤑ 
Either :



Hope I helped ! ♡
Have a wonderful day / night ! ツ
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Answer:
This really isn't a question. I can help you out with writing one.
John randomly selected 45% of seventh grade students in his school and asked them what their favorite time to play sports was. Of the students surveyed, 51 prefer to play sports after school. Based on this data, what is the most reasonable prediction of seventh graders in his entire grade?
Step-by-step explanation:
To answer my question, you would set up a proportion.
<-- the answer to that question will will be 113.
Answer:
Every week, the mass of the sample is multiplied by a factor of 0.81
Step-by-step explanation:
Let's rewrite the base and find the expression whose exponent is just ttt.
(0.97)7t+5=(0.97)7t⋅(0.97)5=(0.977)t⋅(0.97)5
Therefore, we can rewrite the modeling function as follows.
M(t)=(0.97)5⋅(0.977)t
According to this model, the mass of the sample is multiplied by 0.977 every week. Rounding this to two decimal places, we get 0.977≈0.81.
The answer is 23 1/3. First, you need to add 280 to both sides of the equations in order cancel out 280 and get 12x by itself. But remember whatever you do to one side of an equation, you must to do the other. So now you have 12x=280. Now divide both sides of the equation by 12 in order to get x completely isolated. 280 divided by twelve is 23 1/3.
Answer:
never did this with big numbers but i will try lol! okay so the word "is" means the number after that with be of the top. And the word "of" (and the nummber after that) will always be on the bottom. so remember is/of
Step-by-step explanation:
5% so you will have 5/100
IS $70,000 (70,000 will be on the top of your fraction)
and you know what ill just give you the dang answer LOL!
is your answer 1,400,000? if so thats the answer