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mr Goodwill [35]
3 years ago
14

What will be the final speed of an electron released from rest at the negative plate?

Chemistry
1 answer:
Scrat [10]3 years ago
6 0
Potential energy U= k*Q*q/r
doubling the charge Q doubles the potential energy. Since this will just be converted into kinetic energy u will double tht
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A precipitate forms when mixing solutions of sodium fluoride (NaF) and lead II nitrate (Pb(NO3)2). Complete and balance the net
Leya [2.2K]

Answer:

See explanation

Explanation:

The molecular equation shows all the compounds involved in the reaction.

The molecular equation is as follows;

2NaF(aq) + Pb(NO3)2(aq) -------> PbF2(s) + 2NaNO3(aq)

The complete ionic equation shows all the ions involved in the reaction

The complete ionic equation;

2Na^+(aq) + 2F^-(aq) + Pb^2+(aq) + 2NO3^-(aq) -------->PbF(s) + 2Na^+(aq) +2NO3^-(aq)

The net Ionic equation shows the ions that actually participated in the reaction

The net ionic equation is;

2F^-(aq) + Pb^2+(aq)--------> PbF(s)

3 0
3 years ago
Which of the following molecules has the same empirical formula as glucose (C6H1206)
timama [110]

Answer:

ethanoic acid

Explanation:

as it also contains carbon dioxide water and oxygen as glucose

hope it helps you

please mark me as brainlist

4 0
3 years ago
Read 2 more answers
When cells or organisms maintain a stable internal state in a changing environment is called?
Goryan [66]

Answer:

Homeostasis

Explanation:

8 0
4 years ago
How can energy from the Sun be used to heat water? What
worty [1.4K]

Answer:

Water is heated as it travels through flat, glazed panels known as solar collectors, which are normally situated on the roof of the building. The heated water is then stored in an insulated storage tank.

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3 years ago
How many molecules of CH4 are in 24.1 g of this compound?
jok3333 [9.3K]

<u>1) find molar mass of CH₄</u>

=12.01+4(1.01)\\\\=16.05\ g/mol

<u>2) determine moles of CH₄</u>

=24.1g\ CH_{4}\ x\ \frac{1\ mol\ CH_{4}}{16.05g\ CH_{4}}\\\\=1.501557632\ mol\ CH_{4}

<u>3) multiply by avogadro's number</u>

=1.501557632\ mol\ CH_{4}\ x\ \frac{6.022\ x\ 10^{23}\ molecules\ CH_{4}}{1\ mol\ CH_{4}} \\\\=9.04238006\ x\ 10^{23}\\\\=9.04\ x\ 10^{23}\ molecules\ CH_{4}

7 0
2 years ago
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