HCl is <span>limiting reactant, Mg in excess therefore:
</span><span>number of moles HCl:
75.0 mL in liters: 75.0 / 1000 => 0.075 L
Molarity HCl = 1.0 M
n = M x V
n = 1.0 x 0.075
n = 0.075 moles of HCl
</span>Mg(s) + 2 HCl (aq) = H2 (g) + MgCl2 (aq)
<span>2 moles HCl -------------------- 1 mole H2
</span><span>0.075 moles of HCl ------------ ( moles H2)
</span>
moles H2 = 0.075 x 1 / 2
moles H2 = 0.075 / 2
= 0.0375 moles of H2
hope this helps!
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p
K
a
=
5.4
pH
=
3.7
Explanation:
p
K
a
is simply
−
log
10
(
K
a
)
. It is a constant at any temperature and does not depend on the molarity of the solution.
p
K
a
=
−
log
10
(
K
a
)
=
−
log
10
(
4.0
×
10
−
6
)
=
5.4Explanation:
1. Change in temperature
2. Odour being produced
3. Gas bubbles being formed
4. Solid precipitate is formed
5. Permanent change in colour
6. Light is being produced
The product for the following reaction are :
- 2 - butanone
- CH₃CH₂COCl
- CH₃CH₂CONHCH₃
T carboxylic acid is an organic compound. the functional group of carboxylic acid is carboxy. general formula is given as : R - COO⁻.
The reactions are given as follows :
1) the reduction of carboxylic acid into ketone with the organometallic compound is given as follows :
CH₃CH₂COOH + CH₃Li ------> CH₃CH₂COCH₃
2 butanone
2) the reaction of carboxylic acid with SOCl₂ is given as follows :
CH₃CH₂COOH + SOCl₂ -----> CH₃CH₂COCl
3) the reaction of carboxylic acid with CH₃NH₂ is given as follows
CH₃CH₂COOH + CH₃NH₂ -----> CH₃CH₂CONHCH₃
Thus, The product for the following reaction are :
- 2 - butanone
- CH₃CH₂COCl
- CH₃CH₂CONHCH₃
To learn more about carboxylic acid here
brainly.com/question/4721247
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