Answer:
3.26 % of vinegar is acetic acid
Explanation:
Step 1: Data given
Mass of the sample = 5.54 grams
Volume of NaOH = 30.10 mL
Molarity of NaOH = 0.100M
Step 2: The balanced equation
CH3COOH + NaOH → CH3COONa + H2O
Step 3: Calculate moles NaOH
Moles NaOH = volume * molarity
Moles NaOH = 0.03010 L * 0.100M
Moles NaOH = 0.00301 moles NaOH
Step 4: Calculate moles CH3COOH
For 1 mol NaOH we need 1 mol CH3COOH
For 0.00301 moles NaOH we nee 0.00301 moles CH3COOH
Step 5: Calculate mass CH3COOH
Mass CH3COOH = moles CH3COOH * molar mass CH3COOH
Mass CH3COOH = 0.00301 moles * 60.05 g/mol
Mass CH3COOH = 0.1808 grams
Step 6: Calculate percent by weight of acetic acid
Mass % = ( 0.1808 / 5.54 ) *100%
Mass % = 3.26 %
3.26 % of vinegar is acetic acid
