Answer:
26.8g
Explanation:
The formula of the compound given is:
Cu₂CrO₄
Given:
Number of moles = 0.11
To find the mass, we use the expression below:
Mass = number of moles x molar mass
Molar mass of Cu₂CrO₄ = 2(63.6) + 52 + 4(16) = 243.2g/mol
Now insert the parameters and solve;
Mass = 0.11 x 243.2 = 26.8g
The amount of energy in kilocalories released from 49 g of glucose given the data is -4.4 Kcal
How to determine the mole of glucose
Mass of glucose = 49 g
Molar mass of glucose = 180.2 g/mol
Mole of glucose = ?
Mole = mass / molar mass
Mole of glucose = 49 / 180.2
Mole of glucose = 0.272 mole
How to determine the energy released
C₆H₁₂O₆ →2C₂H₆O + 2CO₂ ΔH = -16 kcal/mol
From the balanced equation above,
1 mole of glucose released -16 kcal of energy
Therefore,
0.272 mole of glucose will release = 0.272 × -16 = -4.4 Kcal
Thus, -4.4 Kcal were released from the reaction
Learn more about stoichiometry:
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A covenant bond is formed when electrons move from one element to another.
