The first ionization energy, E , of a nitrogen atom is 2.32 aJ. What is the wavelength of light, in nanometers, that is just suf
ficient to ionize a nitrogen atom? Values for constants can be found in the Chempendix.
1 answer:
Answer:
Required wavelength of light is 85.6 nm.
Explanation:
E = h×ν =
E = Energy in J
ν = frequency (Hz s-1)
λ = wavelength in m
Planck constant h = J s
c = speed of light = m s-1
2.32 aJ = J
E = h×ν
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