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max2010maxim [7]
3 years ago
6

How do you think the temperatures of these two cooking appliances compare?

Chemistry
1 answer:
asambeis [7]3 years ago
6 0
What is the two coking appliances 

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Describe how magnetic forces and electric forces are similar and different from each other
PtichkaEL [24]

<em>ANSWER:</em>

Objects that have the same charge, both positive or both negative, repel each other, and those with opposite charges attract each other. ... Similar to electric charges, opposite poles attract, and like poles repel. The stronger the magnets and the closer together they are, the stronger the magnetic force between them.

4 0
3 years ago
Hat is used and produced in glycoloysis?
agasfer [191]

During glycolysis is used glucose, ADP and pyruvate and produce ATP, water and NADH.

<h3>What is glycolysis?</h3>

Glycolysis is the first step of cellular respiration by which glucose is used to generate energy in the form of ATP.

Cellular respiration has three sequential steps, i.e., glycolysis, the Krebs cycle and oxidative phosphorylation.

Glycolysis is the cellular respiration step that generates 2 net high energy ATP molecules and 2 reduced NADH.

In conclusion, glycolysis uses glucose, pyruvate and ADP to generate ATP, water and Nicotinamide adenine dinucleotides (NADH).

Learn more about glycolysis here:

brainly.com/question/737320

#SPJ1

5 0
2 years ago
How many mol of hydrogen in 2.8 mol of caffeine.
pochemuha
Empirical formula of caffeine is C₈H₁₀N₄O₂.

In 1 mol of caffeine we have 10 mol of hydrogen.
In 2,8 mol of caffeine we have x mol of hydrogen.

x = 2,8 mol * 10 mol / 1 mol = 28 mol

ANSWER: There are 28 mol of hydrogen.

:-) ;-)
5 0
3 years ago
Read 2 more answers
Calculate the number of milliliters of 0.440 M KOH required to precipitate all of the Fe2+ ions in 187 mL of 0.692 M FeSO4 solut
EleoNora [17]

Answer:

588.2 mL

Explanation:

  • FeSO₄(aq) + 2KOH(aq) → Fe(OH)₂(s) + K₂SO₄(aq)

First we <u>calculate how many Fe⁺² moles reacted</u>, using the given <em>concentration and volume of FeSO₄ solution</em> (the number of FeSO₄ moles is equal to the number of Fe⁺² moles):

  • moles = molarity * volume
  • 187 mL * 0.692 M = 129.404 mmol Fe⁺²

Then we convert Fe⁺² moles to KOH moles, using the stoichiometric ratios:

  • 129.404 mmol Fe⁺² * \frac{2mmolKOH}{1mmolFeSO_4} = 258.808 mmol KOH

Finally we<u> calculate the required volume of KOH solution</u>, using <em>the given concentration and the calculated moles</em>:

  • volume = moles / molarity
  • 258.808 mmol KOH / 0.440 M = 588.2 mL
6 0
2 years ago
What is the pOH of<br> a<br> 2.6 x 10-6 M H+ solution?
scZoUnD [109]

Answer:

pH = -log 2.6 x 10-6 M

pH = 5.585

pOH= 14 - 5.585 = 8.415

8.4 as 2 sig figs

8 0
3 years ago
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