Under standard conditions, which of the following is the net reaction that occurs in the cell? Cd | Cd2+ | | Cu2+

The Haber Process synthesizes ammonia at elevated temperatures and pressures. Suppose you combine 1580 L of nitrogen gas and 351

ikadub [295]

Answer : The volume of reactant measured at STP left over is 409.9 L

Explanation :

First we have to calculate the moles of $N_2$ and $H_2$ by using ideal gas equation.

For $N_2$ :

$PV_{N_2}=n_{N_2}RT$

where,

P = Pressure of gas at STP = 1 atm

V = Volume of $N_2$ gas = 1580 L

n = number of moles $N_2$ = ?

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of gas at STP = 273 K

Putting values in above equation, we get:

$1atm\times 1580L=n_{N_2}\times (0.0821L.atm/mol.K)\times 273K$

$n_{N_2}=70.49mole$

For $H_2$ :

$PV_{H_2}=n_{H_2}RT$

where,

P = Pressure of gas at STP = 1 atm

V = Volume of $H_2$ gas = 3510 L

n = number of moles $H_2$ = ?

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of gas at STP = 273 K

Putting values in above equation, we get:

$1atm\times 3510L=n_{H_2}\times (0.0821L.atm/mol.K)\times 273K$

$n_{H_2}=156.6mole$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

From the balanced reaction we conclude that

As, 3 mole of $H_2$ react with 1 mole of $N_2$

So, 156.6 moles of $H_2$ react with $\frac{156.6}{3}\times 1=52.2$ moles of $N_2$

From this we conclude that, $N_2$ is an excess reagent because the given moles are greater than the required moles and $H_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the excess moles of $N_2$ reactant (unreacted gas).

Excess moles of $N_2$ reactant = 70.49 - 52.2 = 18.29 moles

Now we have to calculate the volume of reactant, measured at STP, is left over.

$PV=nRT$

where,

P = Pressure of gas at STP = 1 atm

V = Volume of gas = ?

n = number of moles of unreacted gas = 18.29 moles

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of gas at STP = 273 K

Putting values in above equation, we get:

$1atm\times V=18.29mole\times (0.0821L.atm/mol.K)\times 273K$

$V=409.9L$

Therefore, the volume of reactant measured at STP left over is 409.9 L

8 0

2 years ago

In your chemistry class, your instructor fills three different flasks with three different gases. She tells you that one gas is

Digiron [165]

air in the first

oxygen in the second

CO2 in the third

6 0

2 years ago

Write balanced complete ionic equation for K2SO4(aq)+CaI2(aq)→CaSO4(s)+KI(aq)

dangina [55]

K₂SO₄ + CaI₂ → CaSO₄ + KI

  K: 2 K: 1
S: 1 S: 1
  O: 4 O: 4
Ca: 1 Ca: 1
  I: 2 I: 1
↓
K₂SO₄ + CaI₂ → CaSO₄ + 2KI

  K: 2 K: 2
S: 1 S: 1
  O: 4 O: 4
Ca: 1   Ca: 1
  I: 2 I: 2

4 0

2 years ago

1. Assume this experiment (after the extractions are complete) left you with 4 pure products (aspirin, acetaminophen and caffein

crimeas [40]

Answer:

Explanation:

Out of aspirin, acetaminophen and caffeine, aspirin is an acid because it is acetyl saliciylic acid . Hence it can be tested with litmus paper .

acetaminophen contains phenolic functional group , hence it is a weak acid . It can be tested with any test with which phenol test are done, like with neutral solution of ferric chloride .

caffeine is weak basic substance . It can also be tested with the help of testing a basic substance .

4 0

2 years ago

Which solution turns litmus paper blue A.acidic B.basic C.neutral D.none

Wittaler [7]

Question: Which solution turns litmus paper blue

Answer: basic

Explanation:compound dissolves in water which cause the solution to become alkaline

question answered by

(jacemorris04)

8 0

2 years ago

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Under standard conditions, which of the following is the net reaction that occurs in the cell? Cd | Cd2+ | | Cu2+ | Cu