Answer:
(-1) is the slope of a graph of In(y+3) on the vertical axis versus In(x-2) on the horizontal axis.
Explanation:
Taking natural logarithm on both the sides:
![\ln [(y+3)]-\ln[2]=\ln [b]-\ln [(x-2)]](https://tex.z-dn.net/?f=%5Cln%20%5B%28y%2B3%29%5D-%5Cln%5B2%5D%3D%5Cln%20%5Bb%5D-%5Cln%20%5B%28x-2%29%5D)
![\ln [(y+3)]=\ln[2]+\ln [b]-\ln [(x-2)]](https://tex.z-dn.net/?f=%5Cln%20%5B%28y%2B3%29%5D%3D%5Cln%5B2%5D%2B%5Cln%20%5Bb%5D-%5Cln%20%5B%28x-2%29%5D)
![\ln [(y+3)]=\ln {[2\times b]-\ln [(x-2)]](https://tex.z-dn.net/?f=%5Cln%20%5B%28y%2B3%29%5D%3D%5Cln%20%7B%5B2%5Ctimes%20b%5D-%5Cln%20%5B%28x-2%29%5D)
Slope intercept form is generally given as:
m = slope, c = intercept on y axis or vertical axis
On rearranging equation:
![\ln [(y+3)]=(-1)\times \ln [(x-2)]+\ln {2b}](https://tex.z-dn.net/?f=%5Cln%20%5B%28y%2B3%29%5D%3D%28-1%29%5Ctimes%20%5Cln%20%5B%28x-2%29%5D%2B%5Cln%20%7B2b%7D)
y = ln [(y+3)], x = ln [(x-2)], m=-1 , c = ln 2b
(-1) is the slope of a graph of In(y+3) on the vertical axis versus In(x-2) on the horizontal axis.
Answer:
They are both pretty soft for metals, but magnesium is significantly harder than calcium using this scale . Mg = 2.5, Ca = 1.75. The larger the number, the harder
Explanation:
Answer:
0.00011765 M
Explanation:
When a solution is prepared by dilution, the volumes and concentrations are related by:
C1*V1 = C2*V2
Where C1 is the concentration of the solution 1, V1 is the volume of the solution 1, C2 is the concentration of solution 2, and V2 is the volume of solution 2.
The stock solution is the solution 1, and the standard solution, the solution 2, so:
0.0001974*29.80 = C2*50.00
C2 = 0.00011765 M
Answer:
1.0
Explanation:
Hydrochloric acid is a strong acid, that is, an acid that dissociates completely, according to the following reaction.
HCl(aq) → H⁺(aq) + Cl⁻(aq)
Then, the concentration of H⁺ will be equal to the initial concentration of the acid, i.e., 0.10 M.
We can calculate the pH using the following expression.
pH = -log [H⁺] = -log 0.10 = 1.0
Cu + 2H2SO4 ⟶ CuSO4 + SO2 + 2H20
In left hand side of the equation.
Cu = 1 atom
H = 4 atoms
S = 2 atoms
O = 8 atoms
In right hand side of the equation.
Cu = 1 atom
S = 2 atoms
0 = 8 atoms
H = 4 atoms
• All the atoms are balanced in the left and right side of the equation and it satisfies the law of conservation of mass.
• Equation is balanced and correct.
*See the attachment .
