Question

Which two points are on the graph of M(a) = - 3/4a-12?

Answer 1

Answer:

(-16, 0) and  (0,-12)  are exactly two points on the graph of the given equation.

Step-by-step explanation:

Here, the given expression is : $M(a) = -\frac{3}{4} a-12$

Here, let M(a)  = b

⇒The equation becomes $b = -\frac{3}{4} a-12$

Now, check for all the given points for (a,b)

1) FOR (-9,0)

$RHS is -\frac{3}{4} (-9)-12 = -5.25 \neq 0$

Hence, (-9,0) is NOT on the graph.

2) FOR (-16,0)

Here, LHS = b = 0

and$RHS = -\frac{3}{4} (-16)-12 = 12-12 = 0$

Hence, LHS  =  RHS = 0  So, (-16,0) is  on the graph.

3) FOR (0,12)

Here, LHS = b = 12

$RHS is -\frac{3}{4} (0)-12 = -12 \neq 12$

Hence, (0,12) is NOT on the graph.

4) FOR (0,-12)

Here, LHS = b = -12

$RHS is -\frac{3}{4} (0)-12 = -12$

and LHS = RHS = -12

Hence, (0,-12) is  on the graph.

Hence, (-16, 0) and  (0,-12)  are exactly two points on the graph of the given equation.