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Sladkaya [172]
2 years ago
10

Question 9

Physics
1 answer:
Anastasy [175]2 years ago
4 0

nAnswer:

uyui

Explanation:

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Let's check the relationship

\\ \rm\hookrightarrow g=\dfrac{GM}{r^2}

\\ \rm\hookrightarrow g\propto G

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\\ \rm\hookrightarrow T\propto \dfrac{1}{\sqrt{g}}

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