1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mila [183]
3 years ago
5

KINDLYY FASTT A uniform metre rule of mass 100 g is pivoted at the 60 cm mark. At what point on the meter rule should a mass of

50 g be suspended for it to balance horizontally?

Physics
1 answer:
MakcuM [25]3 years ago
6 0

Answer:

80 cm.

Explanation:

Since the metre rule is 1 m i.e 100 cm it means that the mass of the metre can be obtained at the 50 cm mark.

But the metre is pivoted at the 60 cm.

Please refer to the attached photo for details.

In the attached photo, y is the distance between the mark (that will balance the metre rule when a 50 g mass is hunged) and the pivot.

Thus, we can obtain the value of y as follow:

Anticlock wise moment = Clock wise moment

Anticlock wise moment = 100 × 10

Clock wise moment = y × 50

Anticlock wise moment = Clock wise moment

100 × 10 = y × 50

Divide both side by 50

y = (100 × 10) /50

y = 20 cm

Now, to obtain the mark, B that will balance the metre, we simply add 20 cm to 60 cm ie

B = 60 + 20

B = 80 cm

You might be interested in
A car travels east at a constant velocity. The net force on the car is:
Scrat [10]
F=ma
As velocity is constant, a=0
So, F=0

Hope this helps!
6 0
3 years ago
Can you help me with this?
Natasha2012 [34]

Answer:

no

Explanation:

so basically I am domb so I can not help you

4 0
3 years ago
Which form of the energy is used to generate electrical energy in a tidal power station
Alla [95]

Tidal energy is the form of energy used to generate electrical energy.

7 0
3 years ago
DUE BY MIDNIGHT
olga2289 [7]

Answer:

Option D. 1000 J.

Explanation:

From the question given above, the following data were obtained:

Force (F) applied = 200 N

Distance (s) = 5 m

Time (t) = 10 s

Workdone (Wd) =?

Workdone (Wd) is simply defined as the product of force (F) and distance (s) moved in the direction of the force. Mathematically, it is expressed as:

Wd = F × s

With the above formula, we can calculate the Workdone as illustrated below:

Force (F) applied = 200 N

Distance (s) = 5 m

Workdone (Wd) =?

Wd = F × s

Wd = 200 × 5

Wd = 1000 J

Thus, the Workdone is 1000 J

8 0
3 years ago
The minute and hour hands of a clock have a common axis of rotation and equal mass. The minute hand is long, thin, and uniform;
bekas [8.4K]

Answer:

b. less than

Explanation:

Moment of inertia decreases as angular velocity increases. Therefore, since the minute hand is faster than the hour hand, it is safe to say that the moment of inertia of the minute hand is less than the moment of inertia of the hour hand?

4 0
3 years ago
Other questions:
  • Which of the following most accurately describes the current understanding of energy? *
    8·1 answer
  • Dr. Perez is part of a team of researchers who are working on designing and building a probe to study solar flares what conditio
    10·2 answers
  • Why is the sky blue and doesn't change color
    12·1 answer
  • A proton orbits a long charged wire, making 1.80 ×106 revolutions per second. The radius of the orbit is 1.20 cm What is the wir
    12·1 answer
  • A Chinook (King) salmon (Genus Oncorynchus) can jump out of water with a speed of 6.75 m / s . If the salmon is in a stream with
    7·1 answer
  • How far will a rubber ball fall in 10 seconds?
    9·1 answer
  • What two quantities do you have to know to calculate the density of and object?
    9·1 answer
  • Daffy Duck is standing 6.8 m away from Minnie Duck. The attractive gravitational force between them is 5.4x10-8 N. If Daffy Duck
    8·1 answer
  • Someone is whirling a hammer that has a mass of 8.5 kg in the air that is tied to a Chain 1.5 m long in a circle that makes 1 re
    8·1 answer
  • I WILL MARK BRAINLIEST TO WHOEVER GETS THIS CORRECT
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!