A double-slit experiment uses light of wavelength 650 nm with a slit separation of 0.100 mm and a screen placed 4.0 m away. a) W
1 answer:
Answer:
Explanation:
a ) Slit separation d = .1 x 10⁻³ m
Screen distance D = 4 m
wave length of light λ = 650 x 10⁻⁹ m
Width of central fringe = λ D / d
=
= 26 mm
b ) Distance between 1 st and 2 nd bright fringe will be equal to width of dark fringe which will also be equal to 26 mm
c ) Angular separation between the central maximum and 1 st order maximum will be equal to angular width of fringe which is equal to
λ / d
=
= 6.5 x 10⁻³ radian.
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<h2><u>We have</u>,</h2>
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- Time taken (t) = 2.9s
- Acceleration due to gravity (g) = + 10 m/s² [Down]
- Final velocity (v)
- Height (h)
→ v = u + gt
→ v = 0 + 10(2.9)
→ v = 29 m/s … ( Ans )
And,
→ h = ut + ½gt²
→ h = 0(2.9) + ½ × 10 × (2.9)²
→ h = 5 × 8.41
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