With what? maybe I can help?
Answer:
W = 270.9 J
Explanation:
given,
F(x) = (12.9 N/m²) x²
work = Force x displacement
dW = F .dx
the push-rod moves from x₁= 1 m to x₂ = 4 m
integrating the above



![W = 12.9\times [\dfrac{x^3}{3}]_1^4 dx](https://tex.z-dn.net/?f=W%20%3D%2012.9%5Ctimes%20%5B%5Cdfrac%7Bx%5E3%7D%7B3%7D%5D_1%5E4%20dx)
`![W = 12.9\times [\dfrac{4^3}{3}-\dfrac{1^3}{3}] dx](https://tex.z-dn.net/?f=W%20%3D%2012.9%5Ctimes%20%5B%5Cdfrac%7B4%5E3%7D%7B3%7D-%5Cdfrac%7B1%5E3%7D%7B3%7D%5D%20dx)
W = 270.9 J
work done by the motor is W = 270.9 J
Answer: +2 e
Explanation: Net charge of a system is sum of charges on all the constituents of the system.
The system contains two spheres. Charge on one sphere is:
q₁ = +6 e
Charge on the second sphere is:
q₂ = -4 e
Net charge of the system is:
q = q₁ + q₂
q = +6 e + (-4 e) = + 2 e
Thus, the net charge of system is +2 e.
<span>A_____ is the amount of heat needed to raise the temperature of 1 kilogram of water 1 degree celsius.
Specific Heat Capacity of Water.
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