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dangina [55]
3 years ago
11

What is a positive impact of artificial fertilizers

Physics
1 answer:
dybincka [34]3 years ago
5 0
<span>The top benefit of pesticides is their effectiveness against pests that would otherwise decimate crops large and small. </span>
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Consider a person sliding down a water slide at constant velocity. what are the forces acting on the person as they slide? are t
Andru [333]

Explanation :

When a person is sliding with constant velocity, the forces that are acting on him are :

(1) Weight, W = mg where g is acceleration due to gravity.

(2) Friction forces acting opposite to the direction of motion.

(3) Normal force.

The forces acting on the person is balanced because the person is sliding with constant velocity.

From figure it is clear that, friction force is balanced by w\ sin\theta and normal is balanced by w\ cos\theta.

4 0
3 years ago
Read 2 more answers
What is the order of magnitude of the distance of Sun to nearest star in meters?
neonofarm [45]

Answer:

Approximating the Milky Way as a disk and using the density in the solar neighborhood, there are about 100 billion stars in the Milky Way.

Explanation:

Since we are making an order of magnitude estimate, we will make a series of simplifying assumptions to get an answer that is roughly right.

Let's model the Milky Way galaxy as a disk.

The volume of a disk is:

V

=

π

⋅

r

2

⋅

h

Plugging in our numbers (and assuming that

π

≈

3

)

V

=

π

⋅

(

10

21

m

)

2

⋅

(

10

19

m

)

V

=

3

×

10

61

m

3

Is the approximate volume of the Milky Way.

Now, all we need to do is find how many stars per cubic meter (

ρ

) are in the Milky Way and we can find the total number of stars.

Let's look at the neighborhood around the Sun. We know that in a sphere with a radius of

4

×

10

16

m there is exactly one star (the Sun), after that you hit other stars. We can use that to estimate a rough density for the Milky Way.

ρ

=

n

V

Using the volume of a sphere

V

=

4

3

π

r

3

ρ

=

1

4

3

π

(

4

×

10

16

m

)

3

ρ

=

1

256

10

−

48

stars /

m

3

Going back to the density equation:

ρ

=

n

V

n

=

ρ

V

Plugging in the density of the solar neighborhood and the volume of the Milky Way:

n

=

(

1

256

10

−

48

m

−

3

)

⋅

(

3

×

10

61

m

3

)

n

=

3

256

10

13

n

=

1

×

10

11

stars (or 100 billion stars)

Is this reasonable? Other estimates say that there are are 100-400 billion stars in the Milky Way. This is exactly what we found.

4 0
2 years ago
Read 2 more answers
If i have a kinematic equation vf^2=vi^2-2*a(xf-xi), how can i solve for xi step by step
azamat

Answer:

Explanation:

v_f^2 = v_i^2-2a(x_f-x_i)

Subtract both sides by v_i^2:

- v_i^2+v_f^2 = -2a(x_f-x_i)

Divide both sides by -2*a:

\frac{v_i^2 - v_f^2}{2a} =x_f-x_i

Add both sides by x_i:

x_i+\frac{v_i^2 - v_f^2}{2a} =x_f

Subtract both sides by \frac{v_i^2 - v_f^2}{2a}:

x_i=x_f-\frac{v_i^2 - v_f^2}{2a}

8 0
3 years ago
Help me with this one aswell, too confused and tired for this
gogolik [260]
D all of the above applies to the functions of the nervous system.
7 0
2 years ago
Does the Earth stay in one place throughout the year? If it doesn't, describe its motion and where it's located in the solar syt
stiv31 [10]

the earth moves throughout the year such as rotate around the sun, so yes the it does move and it sits roughly at 93.048 million miles away from the sun. I hope this helps you out! :)

6 0
3 years ago
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